Pertanyaan

Turunan pertama dari f ( x ) = 5 x + 2 x 2 − 3 a d a l ah f ( x ) . N i l ai f ( 0 ) = ...

Turunan pertama dari $f (x) = \frac{x ^{2} - 3}{5 x + 2} a d a l ah f (x) . N i l ai f (0) = ...$

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

$F u n g s i space b e r b e n t u k space f left parenthesis x right parenthesis equals u over v M a k a space t u r u n a n space p e r ta m a n y a space y a i t u colon f apostrophe left parenthesis x right parenthesis equals fraction numerator u apostrophe. v minus u. v apostrophe over denominator v squared end fraction D i k e t a h u i colon f left parenthesis x right parenthesis equals fraction numerator x squared minus 3 over denominator 5 x plus 2 end fraction M i s a l colon u equals x squared minus 3 space left right arrow u apostrophe equals 2 x v equals 5 x plus 2 left right arrow v apostrophe equals 5 M a k a f apostrophe left parenthesis x right parenthesis equals fraction numerator 2 x left parenthesis 5 x plus 2 right parenthesis minus left parenthesis x squared minus 3 right parenthesis left parenthesis 5 right parenthesis over denominator left parenthesis 5 x plus 2 right parenthesis squared end fraction f apostrophe left parenthesis x right parenthesis equals fraction numerator 10 x squared plus 4 x minus 5 x squared plus 15 over denominator left parenthesis 5 x plus 2 right parenthesis squared end fraction f apostrophe left parenthesis x right parenthesis equals fraction numerator 5 x squared minus 4 x plus 15 over denominator left parenthesis 5 x plus 2 right parenthesis squared end fraction f apostrophe left parenthesis 0 right parenthesis equals fraction numerator 5 left parenthesis 0 right parenthesis minus 4 left parenthesis 0 right parenthesis plus 15 over denominator left parenthesis 5 left parenthesis 0 right parenthesis plus 2 right parenthesis squared end fraction f apostrophe left parenthesis 0 right parenthesis equals 15 over 4$