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Pertanyaan

Turunan pertama dari f ( x ) = 5 x + 2 x 2 − 3 ​ a d a l ah f ( x ) . N i l ai f ( 0 ) = ...

Turunan pertama dari

 

  1. negative 17 over 4

  2. negative 15 over 4

  3. 6 over 4

  4. 15 over 4

  5. 17 over 4

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Pembahasan

F u n g s i space b e r b e n t u k space f left parenthesis x right parenthesis equals u over v  M a k a space t u r u n a n space p e r ta m a n y a space y a i t u colon  f apostrophe left parenthesis x right parenthesis equals fraction numerator u apostrophe. v minus u. v apostrophe over denominator v squared end fraction  D i k e t a h u i colon  f left parenthesis x right parenthesis equals fraction numerator x squared minus 3 over denominator 5 x plus 2 end fraction  M i s a l colon  u equals x squared minus 3 space left right arrow u apostrophe equals 2 x  v equals 5 x plus 2 left right arrow v apostrophe equals 5  M a k a  f apostrophe left parenthesis x right parenthesis equals fraction numerator 2 x left parenthesis 5 x plus 2 right parenthesis minus left parenthesis x squared minus 3 right parenthesis left parenthesis 5 right parenthesis over denominator left parenthesis 5 x plus 2 right parenthesis squared end fraction  f apostrophe left parenthesis x right parenthesis equals fraction numerator 10 x squared plus 4 x minus 5 x squared plus 15 over denominator left parenthesis 5 x plus 2 right parenthesis squared end fraction  f apostrophe left parenthesis x right parenthesis equals fraction numerator 5 x squared minus 4 x plus 15 over denominator left parenthesis 5 x plus 2 right parenthesis squared end fraction  f apostrophe left parenthesis 0 right parenthesis equals fraction numerator 5 left parenthesis 0 right parenthesis minus 4 left parenthesis 0 right parenthesis plus 15 over denominator left parenthesis 5 left parenthesis 0 right parenthesis plus 2 right parenthesis squared end fraction  f apostrophe left parenthesis 0 right parenthesis equals 15 over 4

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Tentukan turunan pertama dari fungsi berikut. b. g ( t ) = t 3 3 t 2 − 4 t 3 + t 4 ​

2

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