Diketahui f(x)=2x+1x2+3. Nilai f(0)+3f (0) adalah ....

Pertanyaan

Diketahui $straight f left parenthesis straight x right parenthesis equals fraction numerator straight x squared plus 3 over denominator 2 straight x plus 1 end fraction. space Nilai space straight f left parenthesis 0 right parenthesis plus 3 straight f apostrophe left parenthesis 0 right parenthesis space adalah space$ ....

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Menggunakan aturan turunan pembagian fungsi aljabar, maka didapatkan

$table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of apostrophe left parenthesis x right parenthesis end cell equals cell fraction numerator x squared plus 3 over denominator 2 x plus 1 end fraction end cell row blank equals cell fraction numerator 2 x left parenthesis 2 x plus 1 right parenthesis minus open curly brackets 2 open parentheses x squared plus 3 close parentheses close curly brackets over denominator open parentheses 2 x plus 1 close parentheses squared end fraction end cell row blank equals cell fraction numerator 4 x squared plus 2 x minus 2 x squared minus 6 over denominator open parentheses 2 x plus 1 close parentheses squared end fraction end cell row blank equals cell fraction numerator 2 x squared plus 2 x minus 6 over denominator open parentheses 2 x plus 1 close parentheses squared end fraction end cell row cell f to the power of apostrophe left parenthesis 0 right parenthesis end cell equals cell fraction numerator negative 6 over denominator 1 squared end fraction equals negative 6 end cell end table$

Oleh karena itu, jawaban yang benar adalah B.