Roboguru

Titik terletak pada garis . Koordinat titik dan titik . Jika  , koordinat titik adalah .…

Pertanyaan

Titik P terletak pada garis AB. Koordinat titik text A end text space left parenthesis 11 comma 3 comma negative 2 right parenthesis spacedan titik text B  end text left parenthesis 6 comma 8 comma 3 right parenthesis. Jika  AB with rightwards harpoon with barb upwards on top space colon space BP with rightwards harpoon with barb upwards on top equals 5 space colon negative 2, koordinat titik text P end text adalah .…
 

  1. left parenthesis 8 comma 6 comma 2 right parenthesis space

  2. left parenthesis 8 comma 6 comma 1 right parenthesis

  3. left parenthesis 8 comma 4 comma 1 right parenthesis

  4. left parenthesis 4 comma 6 comma 1 right parenthesis space

  5. left parenthesis 4 comma 6 comma 2 right parenthesis

Pembahasan Soal:

Diketahui AB with rightwards harpoon with barb upwards on top space colon space BP with rightwards harpoon with barb upwards on top equals 5 space colon negative 2, maka menggunakan rumus perbandingan vektor:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 3 straight b with rightwards arrow on top plus 2 straight a with rightwards arrow on top over denominator 5 end fraction end cell equals cell straight p with rightwards arrow on top end cell row cell fraction numerator 3 open parentheses table row 6 row 8 row 3 end table close parentheses plus 2 open parentheses table row 11 row 3 row cell negative 2 end cell end table close parentheses over denominator 5 end fraction end cell equals cell straight p with rightwards arrow on top end cell row cell fraction numerator open parentheses table row 18 row 24 row 9 end table close parentheses plus open parentheses table row 22 row 6 row cell negative 4 end cell end table close parentheses over denominator 5 end fraction end cell equals cell straight p with rightwards arrow on top end cell row cell fraction numerator open parentheses table row 40 row 30 row 5 end table close parentheses over denominator 5 end fraction end cell equals cell straight p with rightwards arrow on top end cell row cell open parentheses table row 8 row 6 row 1 end table close parentheses end cell equals cell straight p with rightwards arrow on top end cell end table

 

Maka, koordinat titik P adalah left parenthesis 8 comma 6 comma 1 right parenthesisOleh karena itu, jawaban yang benar adalah B

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 20 Juni 2021

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