Tentukan pusat dan jari-jari lingkaran 2x2+2y2−4x−12y=101!

Pertanyaan

Tentukan pusat dan jari-jari lingkaran 2 x squared plus 2 y squared minus 4 x minus 12 y equals 101 factorial

  1. left parenthesis 1 comma 3 right parenthesis semicolon r equals 11 over 2 square root of 2

  2. left parenthesis 3 comma 1 right parenthesis semicolon r equals negative 11 over 2 square root of 2

  3. left parenthesis 1 comma negative 3 right parenthesis semicolon r equals 11 over 2 square root of 2

  4. left parenthesis negative 1 comma negative 3 right parenthesis semicolon r equals 11 square root of 2

  5. left parenthesis negative 3 comma negative 1 right parenthesis semicolon r equals negative 11 square root of 2

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

2 x squared plus 2 y squared minus 4 x minus 12 y minus 101 equals 0 space left right arrow space x squared plus y squared minus 2 x minus 6 y minus 101 over 2 equals 0 space  M a k a space A equals negative 2 comma space B equals negative 6 space d a n space C equals negative 101 over 2  P u s a t space M space equals space open parentheses negative 1 half A comma space minus 1 half B close parentheses  M equals open parentheses negative 1 half left parenthesis negative 2 right parenthesis comma space minus 1 half left parenthesis negative 6 right parenthesis close parentheses equals left parenthesis 1 comma 3 right parenthesis  r equals square root of 1 fourth.4 plus 1 fourth.36 plus 101 over 2 end root  r equals square root of 1 plus 9 plus 101 over 2 end root  r equals square root of 121 over 2 end root equals 11 over 2 square root of 2

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