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Pertanyaan

Tentukan persamaan lingkaran dengan titik pusat left parenthesis 2 comma 3 right parenthesis dan Melalui titik A left parenthesis 4 comma 6 right parenthesis!

G. Albiah

Master Teacher

Mahasiswa/Alumni Universitas Galuh Ciamis

Jawaban terverifikasi

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell x subscript 1 end cell equals cell 2 comma space y subscript 1 equals 3 end cell row cell x subscript 2 end cell equals cell 4 comma space y subscript 2 equals 6 end cell row r equals cell square root of open parentheses x subscript 2 minus x 1 close parentheses squared plus open parentheses y subscript 2 minus y subscript 1 close parentheses squared end root end cell row blank equals cell square root of open parentheses 4 minus 2 close parentheses squared plus open parentheses 6 minus 3 close parentheses squared end root end cell row blank equals cell square root of 2 squared plus 3 squared end root end cell row blank equals cell square root of 4 plus 9 end root end cell row blank equals cell square root of 13 end cell end table

Selanjutnya kita cari persamaan lingkaran yang berpusat di left parenthesis 2 comma 3 right parenthesis dan berjari-jari square root of 13

table attributes columnalign right center left columnspacing 0px end attributes row a equals cell 2 comma space b equals 3 comma space r equals square root of 13 end cell row cell left parenthesis x minus a right parenthesis squared plus left parenthesis y minus b right parenthesis squared end cell equals cell r squared space end cell row cell left parenthesis x minus 2 right parenthesis squared plus left parenthesis y minus 3 right parenthesis squared end cell equals cell open parentheses square root of 13 close parentheses squared space end cell row cell x squared minus 4 x plus 4 plus y squared minus 6 y plus 9 end cell equals 13 row cell x squared plus y squared minus 4 x minus 6 y plus 4 plus 9 minus 13 end cell equals 0 row cell x squared plus y squared minus 4 x minus 6 y end cell equals 0 end table

Jadi, persamaan lingkarannya adalah Error converting from MathML to accessible text..

 

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