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Proyeksi ortogonal vektor pada adalah ...

Proyeksi ortogonal vektor a space ⃗ equals 4 i space ̂ plus j space ̂ plus 3 k space ̂ pada b space ⃗ equals 2 i space ̂ plus j space ̂ plus 3 k space ̂ adalah ...

  1. 13 over 14 space left parenthesis 2 i space plus j space plus 3 k space space right parenthesis

  2. 15 over 14 space left parenthesis 2 i space plus j space plus 3 k space space right parenthesis

  3. 8 over 7 space left parenthesis 2 i space plus j space plus 3 k space space right parenthesis

  4. 9 over 7 space left parenthesis 2 i space plus j space plus 3 k space space right parenthesis

  5. 4 i space ̂ plus 2 j space ̂ plus 6 k space ̂

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

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Proyeksi ortogonal vektor pada adalah

Proyeksi ortogonal vektor a space ⃗ equals 4 i space ̂ plus j space ̂ plus 3 k space ̂ pada b space ⃗ equals 2 i space ̂ plus j space ̂ plus 3 k space ̂ adalah

open parentheses fraction numerator a with rightwards arrow on top bullet b with rightwards arrow on top over denominator open vertical bar b with rightwards arrow on top close vertical bar squared end fraction close parentheses b with rightwards arrow on top equals open parentheses fraction numerator open parentheses 4 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses bullet open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses over denominator open vertical bar 2 i with hat on top plus j with hat on top plus 3 k with hat on top close vertical bar squared end fraction close parentheses open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses  equals open parentheses fraction numerator 4 bullet 2 plus 1 bullet 1 plus 3 bullet 3 over denominator open parentheses square root of 2 squared plus 1 squared plus 3 squared end root close parentheses squared end fraction close parentheses open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses equals open parentheses fraction numerator 8 plus 1 plus 9 over denominator open parentheses square root of 4 plus 1 plus 9 end root close parentheses squared end fraction close parentheses open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses  equals open parentheses 18 over open parentheses square root of 14 close parentheses squared close parentheses open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses equals open parentheses 18 over 14 close parentheses open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses equals 9 over 7 open parentheses 2 i with hat on top plus j with hat on top plus 3 k with hat on top close parentheses

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Diketahui titik A ( 2 , 3 , − 1 ) , titik B ( − 2 , − 4 , 3 ) , dan vektor p ​ = 4 i − 3 j ​ + k . b.Tentukan proyeksi vektorortogonal vektor p ​ pada arah AB .

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