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Persamaan lingkaran yang berpusat di titik (2, -1) dan berdiameter adalah.....

Persamaan lingkaran yang berpusat di titik (2, -1) dan berdiameter 4 square root of 10 adalah.....

  1. x squared plus y squared minus 4 x minus 2 y minus 35 equals 0

  2. x squared plus y squared minus 4 x plus 2 y minus 35 equals 0

  3. x squared plus y squared minus 4 x plus 2 y minus 33 equals 0

  4. x squared plus y squared plus 4 x minus 2 y minus 35 equals 0

  5. x squared plus y squared plus 4 x minus 2 y minus 33 equals 0

Jawaban:

straight d equals 4 square root of 10 rightwards double arrow straight r equals 2 square root of 10 Persamaan space lingkaran space dengan space pusat space left parenthesis straight a comma space straight b right parenthesis space dan space jari space – space jari space straight r space adalah open parentheses straight x minus straight a close parentheses squared plus open parentheses straight y minus straight b close parentheses squared equals straight r squared Maka space persamaan space lingkaran space dengan space pusat space left parenthesis 2 comma negative 1 right parenthesis space dan space straight r equals 2 square root of 10 open parentheses straight x minus 2 close parentheses squared plus open parentheses straight y plus 1 close parentheses squared equals open parentheses 2 square root of 10 close parentheses squared straight x squared minus 4 straight x plus 4 plus straight y squared plus 2 straight y plus 1 equals 40 straight x squared plus straight y squared minus 4 straight x plus 2 straight y minus 35 equals 0

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