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Nilai-nilai x yang memenuhi pertidaksamaan ∣ x − 2 ∣ ≥ 2 x + 20 ​ adalah ...

Nilai-nilai x yang memenuhi pertidaksamaan adalah ...

  1. begin mathsize 14px style negative infinity less than straight x less or equal than negative 2 union 2 less or equal than straight x less than 10 end style 

  2. begin mathsize 14px style negative infinity less than straight x less or equal than negative 2 union 2 less or equal than straight x less than infinity end style 

  3. begin mathsize 14px style negative infinity less than straight x less or equal than negative 2 union 8 less or equal than straight x less than infinity end style  

  4. begin mathsize 14px style negative 10 less than straight x less or equal than negative 2 union 8 less or equal than straight x less than infinity end style 

  5. begin mathsize 14px style negative 10 less than straight x less or equal than 2 union 8 less or equal than straight x less than infinity end style 

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M. Robo

Master Teacher

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Pembahasan

Syarat dalam akar tak negatif, maka: Kuadrat pertidaksamaan: Buat garis bilangannya: Himpunan penyelesaiannya: {x ≤ -2 atau x ≥ 8} … (Solusi kedua) Irisan kedua solusinya, maka: = {-10 ≤ x ≤ -2 atau x ≥ 8} atau bisa ditulis =

Syarat dalam akar tak negatif, maka:

begin mathsize 14px style square root of 2 straight x plus 20 end root greater or equal than 0 rightwards arrow 2 straight x plus 20 greater or equal than 0 rightwards arrow straight x greater or equal than negative 10 space... space open parentheses solusi space pertama close parentheses end style 

Kuadrat pertidaksamaan:

begin mathsize 14px style open parentheses open vertical bar straight x minus 2 close vertical bar close parentheses squared greater or equal than open parentheses square root of 2 straight x plus 20 end root close parentheses squared open parentheses straight x minus 2 close parentheses squared greater or equal than 2 straight x plus 20 straight x squared minus 4 straight x plus 4 greater or equal than 2 straight x plus 20 straight x squared minus 6 straight x minus 16 greater or equal than 0 open parentheses straight x plus 2 close parentheses open parentheses straight x minus 8 close parentheses equals 0 straight x equals negative 2 space atau space straight x equals 8 end style  

 

Buat garis bilangannya:

Himpunan penyelesaiannya: {x ≤ -2  atau x ≥ 8} … (Solusi kedua)

Irisan kedua solusinya, maka:
= {-10 ≤ x ≤ -2 atau x ≥ 8}  atau bisa ditulis
= begin mathsize 14px style open curly brackets negative 10 less or equal than straight x less or equal than negative 2 union 8 less or equal than straight x less than infinity close curly brackets end style 

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