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Pertanyaan

Nilai balik maksimum dari f ( x ) = 2 1 ​ 2 ​ x + cos x adalah...

Nilai balik maksimum dari  adalah...

  1. straight pi over 16 square root of 3 plus 1 half square root of 2

  2. straight pi over 8 square root of 2 minus 1 half square root of 2

  3. straight pi over 8 square root of 2 plus 1 half square root of 2

  4. straight pi over 8 square root of 2 plus 1 half square root of 3

  5. straight pi over 8 square root of 2 minus 1 half square root of 3

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G. Albiah

Master Teacher

Mahasiswa/Alumni Universitas Galuh Ciamis

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

Pembahasan

Tentukan turunan pertama dari Syarat stasioner Menentukan nilai stasioner, Jadi nilai stasionernya adalah dan . pasti positif karena berada pada kuadran pertama. Oleh karena itu, jawaban yang benar adalah C.

Tentukan turunan pertama dari f left parenthesis x right parenthesis equals 1 half square root of 2 x plus cos space x

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator d over denominator d x end fraction open parentheses 1 half square root of 2 x plus cos open parentheses x close parentheses close parentheses end cell equals cell fraction numerator d over denominator d x end fraction open parentheses fraction numerator x over denominator square root of 2 end fraction plus cos open parentheses x close parentheses close parentheses end cell row blank equals cell fraction numerator d over denominator d x end fraction open parentheses fraction numerator x over denominator square root of 2 end fraction close parentheses plus fraction numerator d over denominator d x end fraction open parentheses cos open parentheses x close parentheses close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 2 end fraction fraction numerator d over denominator d x end fraction open parentheses x close parentheses minus sin open parentheses x close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 2 end fraction times thin space 1 minus sin open parentheses x close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 2 end fraction minus sin open parentheses x close parentheses end cell row blank equals cell 1 half square root of 2 minus sin open parentheses x close parentheses end cell end table

Syarat stasioner f apostrophe left parenthesis x right parenthesis equals 0

table attributes columnalign right center left columnspacing 0px end attributes row cell 1 half square root of 2 minus sin open parentheses x close parentheses end cell equals 0 row cell sin left parenthesis x right parenthesis end cell equals cell 1 half square root of 2 end cell row cell sin space x end cell equals cell 45 degree end cell row cell sin space x end cell equals cell 135 degree end cell end table

Menentukan nilai stasioner,

table attributes columnalign right center left columnspacing 0px end attributes row x equals 45 row cell f left parenthesis 45 right parenthesis end cell equals cell 1 half square root of 2 open parentheses straight pi over 4 close parentheses plus cos 45 degree end cell row blank equals cell straight pi over 8 square root of 2 plus 1 half square root of 2 end cell row blank blank blank row x equals 135 row cell f left parenthesis 135 right parenthesis end cell equals cell 1 half square root of 2 open parentheses fraction numerator 3 straight pi over denominator 4 end fraction close parentheses plus cos 135 end cell row blank equals cell fraction numerator 3 straight pi over denominator 8 end fraction plus 1 half square root of 2 end cell end table

Jadi nilai stasionernya adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets straight pi over 4 comma straight pi over 8 square root of 2 plus 1 half square root of 2 close square brackets end cell end table dan table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets fraction numerator 3 straight pi over denominator 4 end fraction comma fraction numerator 3 straight pi over denominator 8 end fraction plus 1 half square root of 2 close square brackets end cell end table.

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open square brackets straight pi over 4 comma straight pi over 8 square root of 2 plus 1 half square root of 2 close square brackets end cell end table pasti positif karena straight pi over 4 berada pada kuadran pertama. 

 

Oleh karena itu, jawaban yang benar adalah C.

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