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menyatakan jumlah  suku pertama suatu deret geomet...

begin mathsize 14px style S subscript n end style menyatakan jumlah begin mathsize 14px style n end style suku pertama suatu deret geometri dengan rasio  undefined. Nilai dari begin mathsize 14px style fraction numerator S subscript n plus 3 end subscript space minus space S subscript n plus 1 end subscript over denominator S subscript n plus 1 end subscript space minus space S subscript n end fraction equals end style....

  1. begin mathsize 14px style 1 end style 

  2. undefined 

  3. begin mathsize 14px style 4 end style 

  4. undefined 

  5. begin mathsize 14px style 8 end style 

Jawaban:

begin mathsize 14px style fraction numerator S subscript n plus 3 end subscript space minus space S subscript n plus 1 end subscript over denominator S subscript n plus 1 end subscript space minus space S subscript n end fraction equals end style

begin mathsize 14px style fraction numerator fraction numerator a open parentheses r to the power of n plus 3 end exponent minus 1 close parentheses over denominator r minus 1 end fraction minus begin display style fraction numerator a open parentheses r to the power of n plus 1 end exponent minus 1 close parentheses over denominator r minus 1 end fraction end style over denominator fraction numerator a open parentheses r to the power of n plus 1 end exponent minus 1 close parentheses over denominator r minus 1 end fraction minus fraction numerator a open parentheses r to the power of n minus 1 close parentheses over denominator r minus 1 end fraction end fraction equals fraction numerator 2 to the power of n plus 3 end exponent minus 1 minus 2 to the power of n plus 1 end exponent plus 1 over denominator 2 to the power of n plus 1 end exponent minus 1 minus 2 to the power of n plus 1 end fraction equals fraction numerator 2 to the power of n plus 3 end exponent minus 2 to the power of n plus 1 end exponent over denominator 2 to the power of n plus 1 end exponent minus 2 to the power of n end fraction equals fraction numerator 2 to the power of n left parenthesis 2 cubed minus 2 to the power of 1 right parenthesis over denominator 2 to the power of n left parenthesis 2 minus 1 right parenthesis end fraction equals 6 over 1 equals 6 end style 

Jadi, jawaban yang tepat adalah D

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