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Pertanyaan

Jika straight f open parentheses straight x close parentheses equals fraction numerator open parentheses straight x plus 5 close parentheses over denominator open parentheses straight x minus 6 close parentheses end fraction space maka space straight f to the power of negative 1 end exponent open parentheses straight x close parentheses equals...

Pembahasan Soal:

Kita misalkan straight f open parentheses straight x close parentheses equals fraction numerator open parentheses straight x plus 5 close parentheses over denominator open parentheses straight x minus 6 close parentheses end fraction equals straight a maka

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator open parentheses straight x plus 5 close parentheses over denominator open parentheses straight x minus 6 close parentheses end fraction end cell equals straight a row cell ax minus 6 straight a end cell equals cell straight x plus 5 end cell row cell ax minus straight x end cell equals cell 5 plus 6 straight a end cell row cell straight x open parentheses straight a minus 1 close parentheses end cell equals cell 5 plus 6 straight a end cell row straight x equals cell fraction numerator 5 plus 6 straight a over denominator straight a minus 1 end fraction end cell row cell straight f apostrophe open parentheses straight x close parentheses end cell equals cell fraction numerator 5 plus 6 straight a over denominator straight x minus 1 end fraction end cell end table

Jadi hasil dari table attributes columnalign right center left columnspacing 0px end attributes row cell straight f apostrophe open parentheses straight x close parentheses end cell equals cell fraction numerator 5 plus 6 straight a over denominator straight x minus 1 end fraction end cell end table

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 10 Juni 2021

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