Pertanyaan

Jika 16 lo g ( x − 2 ) − 16 lo g ( x 2 − 4 x + 4 ) 1 = − 2 , tentukan nilai x yang memenuhi persamaan tersebut.

Jika $\frac{1}{^{16} lo g ( x - 2 ) - ^{16} lo g ( x ^{2} - 4 x + 4 )} = - 2$ , tentukan nilai $x$ yang memenuhi persamaan tersebut.

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Klaim

S. Amamah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

Ingat sifat-sifat logaritma: Ingat ada persamaan logaritma berlaku jika dan maka dengan syarat , dan . Diketahui maka: diperoleh nilai yang memenuhi atau Syarat numerus 1) syarat numerus 2) Dari syarat numerus mengharuskan . Dengan demikiannilai yang memenuhi adalah .

Ingat sifat-sifat logaritma:

$table attributes columnalign right center left columnspacing 0px end attributes row cell log presuperscript a space b minus log presuperscript a space c end cell equals cell log presuperscript a space b over c end cell row cell log presuperscript a space a to the power of n end cell equals n row cell fraction numerator 1 over denominator log presuperscript a space b end fraction end cell equals cell log presuperscript b space a end cell row cell log presuperscript a to the power of m end presuperscript space b to the power of n end cell equals cell n over m log presuperscript a space b end cell end table$

Ingat ada persamaan logaritma berlaku jika log presuperscript h open parentheses x close parentheses end presuperscript space f open parentheses x close parentheses equals log presuperscript h open parentheses x close parentheses end presuperscript space g open parentheses x close parentheses comma space a greater than 0 dan a not equal to 1 maka dengan syarat , dan .

Diketahui $fraction numerator 1 over denominator log presuperscript 16 space open parentheses x minus 2 close parentheses minus log presuperscript 16 space open parentheses x squared minus 4 x plus 4 close parentheses end fraction equals negative 2$ maka:

$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over denominator log presuperscript 16 space open parentheses x minus 2 close parentheses minus log presuperscript 16 open parentheses x squared minus 4 x plus 4 close parentheses end fraction end cell equals cell negative 2 end cell row cell fraction numerator 1 over denominator log presuperscript 16 space begin display style fraction numerator x minus 2 over denominator x squared minus 4 x plus 4 end fraction end style end fraction end cell equals cell negative 2 end cell row cell fraction numerator 1 over denominator log presuperscript 16 space begin display style fraction numerator x minus 2 over denominator open parentheses x minus 2 close parentheses open parentheses x minus 2 close parentheses end fraction end style end fraction end cell equals cell negative 2 end cell row cell fraction numerator 1 over denominator log presuperscript 16 space begin display style fraction numerator 1 over denominator x minus 2 end fraction end style end fraction end cell equals cell negative 2 end cell row cell fraction numerator 1 over denominator log presuperscript 16 space open parentheses x minus 2 close parentheses to the power of negative 1 end exponent end fraction end cell equals cell negative 2 end cell row cell log presuperscript open parentheses x minus 2 close parentheses to the power of negative 1 end exponent end presuperscript space 16 end cell equals cell negative 2 end cell row cell negative log presuperscript open parentheses x minus 2 close parentheses end presuperscript space 16 end cell equals cell negative 2 end cell row cell log presuperscript open parentheses x minus 2 close parentheses end presuperscript space 16 space end cell equals 2 row cell log presuperscript open parentheses x minus 2 close parentheses end presuperscript space 16 end cell equals cell log presuperscript open parentheses x minus 2 close parentheses end presuperscript space open parentheses x minus 2 close parentheses squared end cell row 16 equals cell open parentheses x minus 2 close parentheses squared end cell row 16 equals cell x squared minus 4 x plus 4 end cell row cell x squared minus 4 x plus 4 minus 16 end cell equals 0 row cell x squared minus 4 x minus 12 end cell equals 0 row cell open parentheses x minus 6 close parentheses open parentheses x plus 2 close parentheses end cell equals 0 end table$

diperoleh nilai yang memenuhi x equals 6 atau x equals negative 2

Syarat numerus 1)

table attributes columnalign right center left columnspacing 0px end attributes row cell x minus 2 end cell greater than 0 row x greater than 2 end table

syarat numerus 2)

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 4 x plus 4 end cell greater than 0 row cell open parentheses x minus 2 close parentheses open parentheses x minus 2 close parentheses end cell greater than 0 row x greater than 2 end table

Dari syarat numerus mengharuskan x greater than 2 . Dengan demikian nilai yang memenuhi adalah x equals 6 .