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Jika , maka nilai dari 5 ​ lo g x + x ​ + 5 ​ adalah ....

Jika begin mathsize 14px style log presubscript presuperscript 4 invisible function application open parentheses log presubscript presuperscript 2 invisible function application x close parentheses plus log presubscript presuperscript 2 invisible function application open parentheses log presubscript presuperscript 4 invisible function application x close parentheses equals 2 end style, maka nilai dari  adalah ....

  1. begin mathsize 14px style 1 end style

  2. begin mathsize 14px style 2 end style

  3. begin mathsize 14px style 4 end style

  4. begin mathsize 14px style 5 end style

  5. begin mathsize 14px style 16 end style

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Perhatikan perhitungan berikut ini! Dengan demikian, didapat hasil sebagai berikut. Jadi, jawaban yang tepatadalah A. Untuk mempelajarinya lebih jelas, tonton video selanjutnya.

Perhatikan perhitungan berikut ini!

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell log presubscript blank presuperscript 4 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis plus log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 4 invisible function application x right parenthesis end cell equals 2 row cell log presubscript blank presuperscript 2 squared end presuperscript invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis plus log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 squared end presuperscript invisible function application x right parenthesis end cell equals 2 row cell 1 half times log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis plus log presubscript blank presuperscript 2 invisible function application open parentheses 1 half open parentheses log presubscript blank presuperscript 2 invisible function application x close parentheses close parentheses end cell equals 2 row cell 1 half times log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis plus log presubscript blank presuperscript 2 invisible function application 1 half plus log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis end cell equals 2 row cell 1 half times log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis plus log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis plus log presubscript blank presuperscript 2 invisible function application 1 half end cell equals 2 row cell 3 over 2. log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis minus 1 end cell equals 2 row cell 3 over 2 times log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis end cell equals 3 row cell log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis end cell equals cell 3 times 2 over 3 end cell row cell log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis end cell equals 2 row cell log presubscript blank presuperscript 2 invisible function application left parenthesis log presubscript blank presuperscript 2 invisible function application x right parenthesis end cell equals cell log presubscript blank presuperscript 2 invisible function application 2 squared end cell row cell log presubscript blank presuperscript 2 invisible function application x end cell equals cell 2 squared end cell row cell log presubscript blank presuperscript 2 invisible function application x end cell equals 4 row x equals cell 2 to the power of 4 end cell row x equals 16 end table end style 

Dengan demikian, didapat hasil sebagai berikut.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell log presubscript blank presuperscript 5 invisible function application square root of x plus square root of x plus 5 end root end cell equals cell log presubscript blank presuperscript 5 invisible function application square root of 16 plus square root of 16 plus 5 end root end cell row blank equals cell log presubscript blank presuperscript 5 invisible function application square root of 16 plus 4 plus 5 end root end cell row blank equals cell log presubscript blank presuperscript 5 invisible function application square root of 25 end cell row blank equals cell log presubscript blank presuperscript 5 invisible function application 5 end cell row blank equals 1 end table end style

Jadi, jawaban yang tepat adalah A.

Untuk mempelajarinya lebih jelas, tonton video selanjutnya.

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