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Jika , maka ....

Jika Error converting from MathML to accessible text., maka begin mathsize 14px style open parentheses f open parentheses x minus 1 close parentheses minus f to the power of negative 1 end exponent open parentheses x close parentheses close parentheses equals end style....

  1. begin mathsize 14px style fraction numerator negative 2 x squared minus 3 x plus 4 over denominator x squared plus 2 x end fraction end style 

  2. begin mathsize 14px style fraction numerator x squared minus x minus 2 over denominator x squared plus 2 x end fraction end style 

  3. begin mathsize 14px style negative fraction numerator negative 2 x squared minus 3 x plus 2 over denominator x squared plus 2 x end fraction end style 

  4. begin mathsize 14px style fraction numerator 2 x squared plus 3 over denominator x squared plus x end fraction end style 

  5. begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 2 x squared plus 2 x minus 3 over denominator x squared plus x end fraction end cell end table end style 

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K. Putri

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Ganesha

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Perhatikan bahwa Sehingga Selanjutnya, kita cari f(x). Dengan demikian, didapat Jadi, jawaban yang tepat adalah E.

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis 2 minus x right parenthesis end cell equals cell fraction numerator 4 x minus 2 over denominator 4 minus 2 x end fraction end cell row blank equals cell fraction numerator 2 x minus 1 over denominator 2 minus x end fraction end cell row blank equals cell fraction numerator 3 over denominator 2 minus x end fraction minus 2 end cell end table end style

Sehingga

begin mathsize 14px style f to the power of negative 1 end exponent left parenthesis x right parenthesis equals 3 over x minus 2 end style

Selanjutnya, kita cari f(x).

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell f to the power of negative 1 end exponent left parenthesis x right parenthesis end cell equals cell 3 over x minus 2 end cell row cell f to the power of negative 1 end exponent left parenthesis y right parenthesis end cell equals cell 3 over y minus 2 end cell row x equals cell 3 over y minus 2 end cell row cell x plus 2 end cell equals cell 3 over y end cell row y equals cell fraction numerator 3 over denominator x plus 2 end fraction end cell row cell f left parenthesis x right parenthesis end cell equals cell fraction numerator 3 over denominator x plus 2 end fraction end cell end table end style

Dengan demikian, didapat

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses f left parenthesis x minus 1 right parenthesis minus f to the power of negative 1 end exponent left parenthesis x right parenthesis close parentheses end cell equals cell fraction numerator 3 over denominator left parenthesis x minus 1 right parenthesis plus 2 end fraction minus open parentheses 3 over x minus 2 close parentheses end cell row blank equals cell fraction numerator 3 over denominator x plus 1 end fraction minus 3 over x plus 2 end cell row blank equals cell fraction numerator 3 x minus 3 x minus 3 plus 2 x left parenthesis x plus 1 right parenthesis over denominator x left parenthesis x plus 1 right parenthesis end fraction end cell row blank equals cell fraction numerator 2 x squared 2 x minus 3 over denominator x left parenthesis x plus 1 right parenthesis end fraction end cell row blank equals cell fraction numerator 2 x squared plus 2 x minus 3 over denominator x squared plus x end fraction end cell end table end style

Jadi, jawaban yang tepat adalah E.

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