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Pertanyaan

Jika ( y ​ lo g 2 y ) ( 2 ​ lo g y 2 1 ​ ) = 1 − y , maka 8 y = ....

Jika  maka ....

  1. 8

  2. begin mathsize 14px style 1 over 8 end style 

  3. begin mathsize 14px style negative 1 over 8 end style 

  4. begin mathsize 14px style log presubscript space presuperscript 2 invisible function application 3 end style 

  5. begin mathsize 14px style log presubscript presuperscript 3 invisible function application 2 end style 

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S. Lestari

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah B.

jawaban yang tepat adalah B.

Pembahasan

Perhatikan bahwa Dengan demikian, didapat Jadi, jawaban yang tepat adalah B.

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses log presuperscript y invisible function application 2 to the power of y close parentheses open parentheses log presuperscript 2 invisible function application 1 over y squared close parentheses end cell equals cell 1 minus y space end cell row cell open parentheses log presuperscript y invisible function application 2 to the power of y close parentheses open parentheses log presuperscript 2 invisible function application y to the power of negative 2 end exponent close parentheses end cell equals cell 1 minus y end cell row cell space open parentheses log presuperscript y invisible function application 2 to the power of y close parentheses open parentheses negative 2 close parentheses open parentheses log presuperscript 2 invisible function application y close parentheses end cell equals cell 1 minus y end cell row cell negative 2 open parentheses log presuperscript y invisible function application 2 to the power of y close parentheses open parentheses fraction numerator 1 over denominator log presuperscript y invisible function application 2 end fraction close parentheses end cell equals cell 1 minus y end cell row cell negative 2 open parentheses fraction numerator log presuperscript y invisible function application 2 to the power of y over denominator log presuperscript y invisible function application 2 end fraction close parentheses end cell equals cell 1 minus y end cell row cell negative 2 log presuperscript 2 invisible function application 2 to the power of y space end cell equals cell 1 minus y end cell row cell log presuperscript 2 invisible function application 2 to the power of y space end cell equals cell fraction numerator y minus 1 over denominator 2 end fraction end cell row cell 2 to the power of y end cell equals cell 2 to the power of fraction numerator y minus 1 over denominator 2 end fraction end exponent end cell row y equals cell fraction numerator y minus 1 over denominator 2 end fraction end cell row cell 2 y end cell equals cell y minus 1 end cell row y equals cell negative 1 end cell end table end style

Dengan demikian, didapat begin mathsize 14px style 8 to the power of y equals 8 to the power of negative 1 end exponent equals 1 over 8. end style

Jadi, jawaban yang tepat adalah B.

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