Jika a=(3−4​) dan b=(4−3​) maka ∣∣​b∣∣​a+∣a∣b=...

Pertanyaan

Jika a with bar on top equals open parentheses table row 3 row cell negative 4 end cell end table close parentheses dan b with bar on top equals open parentheses table row 4 row cell negative 3 end cell end table close parentheses maka open vertical bar b with bar on top close vertical bar a with bar on top plus open vertical bar a with bar on top close vertical bar b with bar on top equals... 

  1. open parentheses table row 35 row 35 end table close parentheses 

  2. open parentheses table row cell negative 35 end cell row 35 end table close parentheses 

  3. open parentheses table row 35 row cell negative 35 end cell end table close parentheses 

  4. open parentheses table row 5 row cell negative 5 end cell end table close parentheses 

  5. open parentheses table row cell negative 5 end cell row cell negative 5 end cell end table close parentheses 

R. Hajrianti

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

Pembahasan

Diketahui a with rightwards arrow on top equals open parentheses table row 3 row cell negative 4 end cell end table close parentheses dan b with rightwards arrow on top equals open parentheses table row 4 row cell negative 3 end cell end table close parentheses

Ingat!

  • Jika vektor a with rightwards arrow on top equals open parentheses table row cell a subscript 1 end cell row cell a subscript 2 end cell end table close parentheses atau a with rightwards arrow on top equals left parenthesis a subscript 1 comma space a subscript 2 right parenthesis maka panjang vektor a with rightwards arrow on top adalah open vertical bar a with rightwards arrow on top close vertical bar equals square root of a subscript 1 squared plus a subscript 2 squared end root.
  • Secara aljabar, perkalian vektor dengan skalar di R squared dapat dirumuskan dengan a with rightwards arrow on top equals open parentheses table row cell a subscript 1 end cell row cell a subscript 2 end cell end table close parentheses maka k a with rightwards arrow on top equals k open parentheses table row cell a subscript 1 end cell row cell a subscript 2 end cell end table close parentheses equals open parentheses table row cell k a subscript 1 end cell row cell k a subscript 2 end cell end table close parentheses.

  • Pada vektor, jika a with rightwards arrow on top equals open parentheses table row cell a subscript 1 end cell row cell a subscript 2 end cell end table close parentheses dan b with rightwards arrow on top equals open parentheses table row cell b subscript 1 end cell row cell b subscript 2 end cell end table close parentheses maka a with rightwards arrow on top plus b with rightwards arrow on top equals open parentheses table row cell a subscript 1 plus b subscript 1 end cell row cell a subscript 2 plus b subscript 2 end cell end table close parentheses.

Sehingga:

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell open vertical bar b with rightwards arrow on top close vertical bar a with rightwards arrow on top plus open vertical bar a with rightwards arrow on top close vertical bar b with rightwards arrow on top end cell row blank equals cell square root of 3 squared plus left parenthesis negative 4 right parenthesis squared end root open parentheses table row 3 row cell negative 4 end cell end table close parentheses plus square root of 4 squared plus left parenthesis negative 3 right parenthesis squared end root open parentheses table row 4 row cell negative 3 end cell end table close parentheses end cell row blank equals cell square root of 9 plus 16 end root open parentheses table row 3 row cell negative 4 end cell end table close parentheses plus square root of 9 plus 16 end root open parentheses table row 4 row cell negative 3 end cell end table close parentheses end cell row blank equals cell square root of 25 open parentheses table row 3 row cell negative 4 end cell end table close parentheses plus square root of 25 open parentheses table row 4 row cell negative 3 end cell end table close parentheses end cell row blank equals cell 5 open parentheses table row 3 row cell negative 4 end cell end table close parentheses plus 5 open parentheses table row 4 row cell negative 3 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 5 cross times 3 end cell row cell 5 cross times left parenthesis negative 4 right parenthesis end cell end table close parentheses plus open parentheses table row cell 5 cross times 4 end cell row cell 5 cross times left parenthesis negative 3 right parenthesis end cell end table close parentheses end cell row blank equals cell open parentheses table row 15 row cell negative 20 end cell end table close parentheses plus open parentheses table row 20 row cell negative 15 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell 15 plus 20 end cell row cell negative 20 plus left parenthesis negative 15 right parenthesis end cell end table close parentheses end cell row blank equals cell open parentheses table row 35 row cell negative 35 end cell end table close parentheses end cell end table   

Jadi, jawaban yang tepat adalah C.

206

4.6 (20 rating)

Aris Bumdes

Jawaban tidak sesuai Pembahasan tidak menjawab soal

Pertanyaan serupa

Diketahui vektor a=⎝⎛​3−1−3​⎠⎞​, dan vektor b=⎝⎛​332​⎠⎞​.  a. Hitunglah a⋅b, ∣∣​a∣∣​, dan ∣∣​b∣∣​.  b. Tentukan besar sudut antara vektor a dengan vektor b.

47

4.3

Jawaban terverifikasi

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