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Hitunglah! 2. x → ∞ lim 4 x 3 + 2 x − 1 6 x 2 + 3 x + 1 = ...

Hitunglah!

2. $x \to \infty lim \frac{6 x ^{2} + 3 x + 1}{4 x ^{3} + 2 x - 1} = ...$

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Jawaban terverifikasi

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$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow infinity of fraction numerator 6 x squared plus 3 x plus 1 over denominator 4 x cubed plus 2 x minus 1 end fraction cross times fraction numerator begin display style 1 over x cubed end style over denominator begin display style 1 over x cubed end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of fraction numerator begin display style fraction numerator 6 x squared over denominator x cubed end fraction plus fraction numerator 3 x over denominator x cubed end fraction plus 1 over x cubed end style over denominator begin display style fraction numerator 4 x cubed over denominator x cubed end fraction plus fraction numerator 2 x over denominator x cubed end fraction minus 1 over x cubed end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of fraction numerator begin display style 6 over x plus 3 over x squared plus 1 over x cubed end style over denominator begin display style 4 plus 2 over x squared minus 1 over x cubed end style end fraction end cell row blank equals cell fraction numerator begin display style 6 over infinity plus 3 over infinity plus 1 over infinity end style over denominator begin display style 4 plus 2 over infinity minus 1 over infinity end style end fraction end cell row blank equals cell fraction numerator 0 plus 0 plus 0 over denominator 4 plus 0 minus 0 end fraction end cell row blank equals 0 row blank blank blank end table end style$