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Garis l ≡ 3 x − y − 1 = 0 dirotasi oleh [ O ( 0 , 0 ) , R ( 4 π ​ ) ] . Persamaan bayangan garis l yang terjadi berbentuk .... ( Modifikasi UN 2014 )

Garis  dirotasi oleh . Persamaan bayangan garis  yang terjadi berbentuk ....

(Modifikasi UN 2014)

  1. begin mathsize 14px style 2 x plus 4 y plus square root of 2 equals 0 end style 

  2. begin mathsize 14px style 2 x plus 4 y minus square root of 2 equals 0 end style 

  3. begin mathsize 14px style 4 x plus 2 y minus square root of 2 equals 0 end style 

  4. begin mathsize 14px style 4 x minus 2 y minus square root of 2 equals 0 end style 

  5. begin mathsize 14px style 4 x minus 2 y plus 2 square root of 2 equals 0 end style 

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G. Albiah

Master Teacher

Mahasiswa/Alumni Universitas Galuh Ciamis

Jawaban terverifikasi

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Pembahasan

Diketahui, Dirotasikan oleh Ditanyakan, Bayangan garis Gunakan persamaan matriks berikut. Maka, Maka di dapat dan Masukan ke persamaan garis , Jadi, bayangan garisnya adalah. Oleh karena itu, jawaban yang benar adalah C.

Diketahui,

  • straight l identical to 3 x minus y minus 1 equals 0
  • Dirotasikan oleh  begin mathsize 14px style open square brackets straight O open parentheses 0 comma space 0 close parentheses comma space straight R open parentheses straight pi over 4 close parentheses close square brackets end style 

Ditanyakan,

  • Bayangan garis

Gunakan persamaan matriks berikut.

open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals open parentheses table row cell cos space straight theta end cell cell negative sin space straight theta end cell row cell sin space straight theta end cell cell cos space straight theta end cell end table close parentheses open parentheses table row x row y end table close parentheses

Maka,

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell equals cell open parentheses table row cell cos space 45 end cell cell negative sin space 45 end cell row cell sin space 45 end cell cell cos space 45 end cell end table close parentheses open parentheses table row x row y end table close parentheses end cell row cell open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell equals cell open parentheses table row cell 1 half square root of 2 end cell cell negative 1 half square root of 2 end cell row cell 1 half square root of 2 end cell cell 1 half square root of 2 end cell end table close parentheses open parentheses table row x row y end table close parentheses end cell row cell open parentheses table row x row y end table close parentheses end cell equals cell open parentheses table row cell 1 half square root of 2 end cell cell negative 1 half square root of 2 end cell row cell 1 half square root of 2 end cell cell 1 half square root of 2 end cell end table close parentheses to the power of negative 1 end exponent open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell row blank blank blank row cell open parentheses table row x row y end table close parentheses end cell equals cell fraction numerator 1 over denominator open parentheses begin display style 1 half square root of 2 space end root times 1 half square root of 2 end style close parentheses minus open parentheses begin display style 1 half square root of 2 times negative 1 half square root of 2 end style close parentheses end fraction open parentheses table row cell 1 half square root of 2 end cell cell 1 half square root of 2 end cell row cell negative 1 half square root of 2 end cell cell 1 half square root of 2 end cell end table close parentheses open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell row cell open parentheses table row x row y end table close parentheses end cell equals cell fraction numerator 1 over denominator begin display style 2 over 4 minus open parentheses negative 2 over 4 close parentheses end style end fraction open parentheses table row cell 1 half square root of 2 end cell cell 1 half square root of 2 end cell row cell negative 1 half square root of 2 end cell cell 1 half square root of 2 end cell end table close parentheses open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell row cell open parentheses table row x row y end table close parentheses end cell equals cell fraction numerator 1 over denominator begin display style 1 end style end fraction open parentheses table row cell 1 half square root of 2 end cell cell 1 half square root of 2 end cell row cell negative 1 half square root of 2 end cell cell 1 half square root of 2 end cell end table close parentheses open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell row cell open parentheses table row x row y end table close parentheses end cell equals cell open parentheses table row cell 1 half square root of 2 end cell cell 1 half square root of 2 end cell row cell negative 1 half square root of 2 end cell cell 1 half square root of 2 end cell end table close parentheses open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses end cell row cell open parentheses table row x row y end table close parentheses end cell equals cell open parentheses table row cell 1 half square root of 2 x apostrophe plus 1 half square root of 2 y apostrophe end cell row cell negative 1 half square root of 2 x apostrophe plus 1 half square root of 2 y apostrophe end cell end table close parentheses end cell end table

Maka di dapat x equals 1 half square root of 2 x apostrophe plus 1 half square root of 2 y apostrophe dan y equals negative 1 half square root of 2 x apostrophe plus 1 half square root of 2 y apostrophe

Masukan ke persamaan garis straight l identical to 3 x minus y minus 1 equals 0,

table attributes columnalign right center left columnspacing 0px end attributes row cell 3 x minus y minus 1 end cell equals 0 row cell 3 open parentheses 1 half square root of 2 x apostrophe plus 1 half square root of 2 y apostrophe close parentheses minus open parentheses negative 1 half x apostrophe plus 1 half square root of 2 y apostrophe close parentheses minus 1 end cell equals 0 row cell 3 over 2 square root of 2 x apostrophe plus 3 over 2 square root of 2 y apostrophe plus 1 half x apostrophe minus 1 half square root of 2 y apostrophe minus 1 end cell equals 0 row cell 4 over 2 square root of 2 x apostrophe plus 2 over 2 square root of 2 y apostrophe minus 1 end cell equals 0 row cell 2 square root of 2 x apostrophe plus square root of 2 y apostrophe minus 1 end cell equals 0 row cell 4 x apostrophe plus 2 y apostrophe minus square root of 2 end cell equals 0 row blank blank blank end table

Jadi, bayangan garisnya adalah .table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank x end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank apostrophe end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank y end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank apostrophe end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 0 end table

Oleh karena itu, jawaban yang benar adalah C.

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