Fungsi f(x) ditentukan oleh f(x)=4−3x4x+3​, x=34​. Jika f−1(x) adalah invers dari , rumus f−1(x−2x−1​) adalah ....

Pertanyaan

Fungsi begin mathsize 14px style f left parenthesis x right parenthesis end style ditentukan oleh size 14px f size 14px left parenthesis size 14px x size 14px right parenthesis size 14px equals fraction numerator size 14px 4 size 14px x size 14px plus size 14px 3 over denominator size 14px 4 size 14px minus size 14px 3 size 14px x end fraction size 14px comma size 14px space size 14px x size 14px not equal to size 14px 4 over size 14px 3. Jika undefined adalah invers dari begin mathsize 14px style f left parenthesis x right parenthesis end style, rumus begin mathsize 14px style f to the power of negative 1 end exponent open parentheses fraction numerator x minus 1 over denominator x minus 2 end fraction close parentheses end style adalah ....

  1. fraction numerator size 14px x size 14px minus size 14px 7 over denominator size 14px 2 size 14px x size 14px minus size 14px 11 end fraction 

  2. fraction numerator size 14px x size 14px minus size 14px 7 over denominator size 14px 2 size 14px x size 14px plus size 14px 11 end fraction 

  3. fraction numerator size 14px 7 size 14px minus size 14px x over denominator size 14px 2 size 14px x size 14px minus size 14px 11 end fraction 

  4. fraction numerator size 14px 7 size 14px minus size 14px x over denominator size 14px 2 size 14px x size 14px plus size 14px 11 end fraction 

  5. fraction numerator size 14px 7 size 14px minus size 14px x over denominator size 14px 11 size 14px minus size 14px 2 size 14px x end fraction 

F. Ayudhita

Master Teacher

Jawaban terverifikasi

Pembahasan

Pembahasan

begin mathsize 14px style f left parenthesis x right parenthesis equals fraction numerator a x plus b over denominator c x plus d end fraction end style,    maka  begin mathsize 14px style space f to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator negative d x plus b over denominator c x minus a end fraction end style

begin mathsize 14px style f left parenthesis x right parenthesis equals fraction numerator 4 x plus 3 over denominator negative 3 x plus 4 end fraction end style, maka  begin mathsize 14px style f to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator negative 4 x plus 3 over denominator negative 3 x minus 4 end fraction end style

begin mathsize 14px style f to the power of negative 1 end exponent space open parentheses fraction numerator x minus 1 over denominator x minus 2 end fraction close parentheses space equals space fraction numerator negative 4 space open parentheses fraction numerator x minus 1 over denominator x minus 2 end fraction close parentheses space space plus 3 over denominator negative 3 space open parentheses begin display style fraction numerator x minus 1 over denominator x minus 2 end fraction end style close parentheses space space minus 4 end fraction space space end style

  begin mathsize 14px style space space equals fraction numerator begin display style fraction numerator negative 4 x plus 4 plus 3 left parenthesis x minus 2 right parenthesis over denominator x minus 2 end fraction end style over denominator begin display style fraction numerator negative 3 x plus 3 minus 4 left parenthesis x minus 2 right parenthesis over denominator x minus 2 space end fraction end style end fraction space space space end style

equals fraction numerator begin mathsize 14px display style fraction numerator negative 4 x plus 4 plus 3 x minus 6 over denominator x minus 2 end fraction end style over denominator begin mathsize 14px display style fraction numerator negative 3 x plus 3 minus 4 x plus 8 over denominator x minus 2 end fraction end style end fraction   

begin mathsize 14px style equals fraction numerator negative left parenthesis x plus 2 right parenthesis over denominator negative left parenthesis 7 x minus 11 right parenthesis end fraction end style

           

begin mathsize 14px style f to the power of negative 1 end exponent open parentheses fraction numerator space x minus 1 over denominator space x minus 2 end fraction close parentheses end style begin mathsize 14px style equals fraction numerator x plus 2 over denominator 7 x minus 11 end fraction end style

Jadi, tidak ada pilihan yang tepat

39

2.5 (2 rating)

Asri Amanda

Makasih ❤️

Pertanyaan serupa

F(x)=4x3x+2​ maka F−1(1)=...

38

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia