Pertanyaan

Invers fungsi dari f ( x ) = 2 x − 1 3 x + 2 , x  ≡ 2 1 adalah...

Invers fungsi dari $f (x) = \frac{3 x + 2}{2 x - 1}, x \neq \equiv \frac{1}{2}$ adalah...

$f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator x plus 2 over denominator 2 x minus 3 end fraction semicolon x not identical to 3 over 2$
$f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator x plus 2 over denominator 3 x plus 1 end fraction semicolon x not identical to negative 1 third$
$f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator 2 x plus 1 over denominator x minus 3 end fraction semicolon x not identical to negative 3$
$f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator x plus 2 over denominator 2 x plus 3 end fraction semicolon x not identical to negative 3 over 2$
$f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator 2 x minus 3 over denominator x plus 5 end fraction semicolon x not identical to negative 5$

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

$M i s a l space f left parenthesis x right parenthesis equals y space m a k a y equals fraction numerator 3 x plus 2 over denominator 2 x minus 1 end fraction 2 x y minus y equals 3 x plus 2 2 x y minus 3 x equals y plus 2 x open parentheses 2 y minus 3 close parentheses equals y plus 2 x equals fraction numerator y plus 2 over denominator 2 y minus 3 end fraction s e h i n g g a space i n v e r s space f to the power of negative 1 end exponent left parenthesis x right parenthesis comma f to the power of negative 1 end exponent left parenthesis x right parenthesis space equals space fraction numerator x plus 2 over denominator 2 x minus 3 end fraction comma x not identical to 3 over 2$