Iklan

Iklan

Pertanyaan

Diketahui vektor-vektor a = i + 2 j ​ , b = 3 i + j ​ , dan c = i + 9 j ​ . Tentukan: a. a + b b. ∣ ∣ ​ a + b ∣ ∣ ​

Diketahui vektor-vektor , dan . Tentukan:

a. 

b. 

Iklan

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

diperoleh dan .

diperoleh a with rightwards arrow on top plus b with rightwards arrow on top equals 4 i with rightwards arrow on top plus 3 j with rightwards arrow on top dan open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals 5.

Iklan

Pembahasan

Gunakan konseppenjumlahan vektor dan panjang vektor. Diketahui vektor-vektor , , dan . a. Akan ditentukan vektor . Penjumlahan vektor secara aljabar dengan menjumlahkan unsur-unsur yang seletak. b. Akan ditentukan . Perhatikan perhitungan berikut. Jadi, diperoleh dan .

Gunakan konsep penjumlahan vektor dan panjang vektor.

m with rightwards arrow on top equals m subscript 1 i with rightwards arrow on top plus m subscript 2 j with rightwards arrow on top rightwards arrow open vertical bar m with rightwards arrow on top close vertical bar equals square root of open parentheses m subscript 1 close parentheses squared plus open parentheses m subscript 2 close parentheses squared end root

Diketahui vektor-vektor a with rightwards arrow on top equals i with rightwards arrow on top plus 2 j with rightwards arrow on topb with rightwards arrow on top equals 3 i with rightwards arrow on top plus j with rightwards arrow on top, dan c with rightwards arrow on top equals i with rightwards arrow on top plus 9 j with rightwards arrow on top.

a. Akan ditentukan vektor a with rightwards arrow on top plus b with rightwards arrow on top.

Penjumlahan vektor secara aljabar dengan menjumlahkan unsur-unsur yang seletak.

table attributes columnalign right center left columnspacing 2px end attributes row cell a with rightwards arrow on top plus b with rightwards arrow on top end cell equals cell open parentheses i with rightwards arrow on top plus 2 j with rightwards arrow on top close parentheses plus open parentheses 3 i with rightwards arrow on top plus j with rightwards arrow on top close parentheses end cell row blank equals cell open parentheses 1 plus 3 close parentheses i with rightwards arrow on top plus open parentheses 2 plus 1 close parentheses j with rightwards arrow on top end cell row blank equals cell 4 i with rightwards arrow on top plus 3 j with rightwards arrow on top end cell end table

b. Akan ditentukan open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar.

Perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 2px end attributes row cell open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar end cell equals cell square root of open parentheses 4 close parentheses squared plus open parentheses 3 close parentheses squared end root end cell row blank equals cell square root of 16 plus 9 end root end cell row blank equals cell square root of 25 end cell row blank equals 5 end table

Jadi, diperoleh a with rightwards arrow on top plus b with rightwards arrow on top equals 4 i with rightwards arrow on top plus 3 j with rightwards arrow on top dan open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals 5.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

11

Iklan

Iklan

Pertanyaan serupa

Diketahui titik-titik: A ( 5 , 2 ) , B ( 4 , 6 ) dan C ( 3 , 2 ) . Jika v = A B + A C maka panjang vektor v = ...

23

4.8

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia