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Diketahui vektor a = ( 0 , − 1 , 3 ) dan b = ( − 2 , 0 , 1 ) . Tentukan: a. ∣ ∣ ​ a + b ∣ ∣ ​

Diketahui vektor . Tentukan:

a.   

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N. Puspita

Master Teacher

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didapatkan: didapatkan: jadi, hasil dari

begin mathsize 14px style a with rightwards arrow on top plus b with rightwards arrow on top end style didapatkan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell a with rightwards arrow on top plus b with rightwards arrow on top end cell equals cell open parentheses table row 0 row cell negative 1 end cell row 3 end table close parentheses plus open parentheses table row cell negative 2 end cell row 0 row 1 end table close parentheses end cell row cell a with rightwards arrow on top plus b with rightwards arrow on top end cell equals cell open parentheses table row cell negative 2 end cell row cell negative 1 end cell row 4 end table close parentheses end cell end table end style 

begin mathsize 14px style open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar end style didapatkan:

begin mathsize 14px style open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals square root of open parentheses negative 2 close parentheses squared plus open parentheses negative 1 close parentheses squared plus 4 squared end root open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals square root of 4 plus 1 plus 16 end root open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals square root of 21 end style 

jadi, hasil dari open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar space adalah space square root of 21 

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