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Diketahui vektor a = ( 2 , − 3 ) , b = ( x , − 1 ) , dan .Tentukan nilai x !

Diketahui vektor , dan open vertical bar a with rightwards arrow on top minus b with rightwards arrow on top close vertical bar equals 5. Tentukan nilai !

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N. Puspita

Master Teacher

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didapat nilai atau .

 didapat nilai x subscript 1 equals 2 plus square root of 21 atau x subscript 2 equals 2 minus square root of 21.

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Ingat: . Menentukan terlebih dahulu. Sehingga Ubah menjadi bentuk kuadrat sempurna. Jadididapat nilai atau .

Ingat:  a with rightwards arrow on top equals open parentheses x subscript a comma space y subscript a close parentheses rightwards arrow open vertical bar a with rightwards arrow on top close vertical bar equals square root of x subscript a superscript 2 plus y subscript a superscript 2 end root.

Menentukan a with rightwards arrow on top minus b with rightwards arrow on top terlebih dahulu.

table attributes columnalign right center left columnspacing 0px end attributes row cell a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell open parentheses table row 2 row cell negative 3 end cell end table close parentheses minus open parentheses table row x row cell negative 1 end cell end table close parentheses end cell row blank equals cell open parentheses 2 minus x comma negative 2 close parentheses end cell end table

Sehingga

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar a with rightwards arrow on top minus b with rightwards arrow on top close vertical bar end cell equals cell square root of left parenthesis 2 minus x right parenthesis squared plus left parenthesis negative 2 right parenthesis squared end root end cell row 5 equals cell square root of 4 minus 4 x plus x squared plus 4 end root end cell row cell 5 squared end cell equals cell open parentheses square root of x squared minus 4 x plus 8 end root close parentheses squared end cell row 25 equals cell x squared minus 4 x plus 8 end cell row 0 equals cell x squared minus 4 x minus 17 end cell end table

Ubah menjadi bentuk kuadrat sempurna.

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared minus 4 x minus 17 end cell equals 0 row cell open parentheses x minus 4 over 2 close parentheses squared minus open parentheses 4 over 2 close parentheses squared minus 17 end cell equals 0 row cell left parenthesis x minus 2 right parenthesis squared minus 21 end cell equals 0 row cell left parenthesis x minus 2 right parenthesis squared end cell equals 21 row cell x minus 2 end cell equals cell plus-or-minus square root of 21 end cell row x equals cell 2 plus-or-minus square root of 21 end cell end table

Jadi didapat nilai x subscript 1 equals 2 plus square root of 21 atau x subscript 2 equals 2 minus square root of 21.

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