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Diketahui titik  dan . Jika  maka nilai  yang meme...

Diketahui titik begin mathsize 14px style straight A open parentheses 7 comma 5 comma 0 close parentheses comma straight B open parentheses 2 comma 4 comma 6 close parentheses end style dan begin mathsize 14px style straight C open parentheses 6 comma straight m comma negative 6 close parentheses end style. Jika begin mathsize 14px style open vertical bar AB with rightwards arrow on top close vertical bar equals open vertical bar AC with rightwards arrow on top close vertical bar end style maka nilai begin mathsize 14px style straight m end style yang memenuhi adalah...

  1. begin mathsize 14px style 0 end style dan begin mathsize 14px style 5 end style 

  2. begin mathsize 14px style 0 end style dan begin mathsize 14px style 10 end style 

  3. begin mathsize 14px style 5 end style dan begin mathsize 14px style 10 end style  space

  4. begin mathsize 14px style negative 1 end style dan begin mathsize 14px style 5 end style space

  5. begin mathsize 14px style 2 end style dan begin mathsize 14px style 10 end style 

Jawaban:

Berdasarkan soal di atas maka dapat dieproleh:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row AB equals cell straight B minus straight A end cell row AB equals cell open parentheses 2 comma 4 comma 6 close parentheses minus open parentheses 7 comma 5 comma 0 close parentheses end cell row AB equals cell open parentheses negative 5 comma negative 1 comma 6 close parentheses end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar AB with rightwards arrow on top close vertical bar end cell equals cell square root of open parentheses negative 5 close parentheses squared plus open parentheses negative 1 close parentheses squared plus 6 squared end root end cell row blank equals cell square root of 25 plus 1 plus 36 end root end cell row blank equals cell square root of 62 end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row AC equals cell straight C minus straight A end cell row AC equals cell open parentheses 6 comma straight m comma negative 6 close parentheses minus open parentheses 7 comma 5 comma 0 close parentheses end cell row AC equals cell open parentheses negative 1 comma straight m minus 5 comma negative 6 close parentheses end cell row blank blank blank row cell open vertical bar AC with rightwards arrow on top close vertical bar end cell equals cell square root of open parentheses negative 1 close parentheses squared plus open parentheses straight m minus 5 close parentheses squared plus open parentheses negative 6 close parentheses squared end root end cell row cell open vertical bar AC with rightwards arrow on top close vertical bar end cell equals cell square root of 1 plus straight m squared minus 10 straight m plus 25 plus 36 end root end cell row cell open vertical bar AC with rightwards arrow on top close vertical bar end cell equals cell square root of straight m squared minus 10 straight m plus 62 end root end cell end table end style 

Dengan demikian:

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar AB with rightwards arrow on top close vertical bar end cell equals cell open vertical bar AC with rightwards arrow on top close vertical bar end cell row cell square root of 62 end cell equals cell square root of straight m squared minus 10 straight m plus 62 end root end cell row 62 equals cell straight m squared minus 10 straight m plus 62 end cell row cell straight m squared minus 10 straight m end cell equals 0 row cell straight m open parentheses straight m minus 10 close parentheses end cell equals cell 0 rightwards double arrow straight m equals 0 space logical or space straight m equals 10 end cell end table end style 

Oleh karena itu, jawaban yang benar adalah B.

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