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Pertanyaan

Diketahui koordinat A ( − 1 , 3 ) dan B ( 3 , 6 ) . c. Tentukan vektor satuan AB .

Diketahui koordinat  dan .

c. Tentukan vektor satuan .

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D. Rajib

Master Teacher

Mahasiswa/Alumni Universitas Muhammadiyah Malang

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Pembahasan

Diketahui : Ditanya : Tentukanvektor satuan dari Jawab : Maka vektor satuan adalah :

Diketahui :

begin mathsize 14px style A left parenthesis negative 1 comma 3 right parenthesis end style 

begin mathsize 14px style B left parenthesis 3 comma 6 right parenthesis end style

Ditanya :

Tentukan vektor satuan dari begin mathsize 14px style stack A B with rightwards arrow on top end style 

Jawab :

begin mathsize 14px style stack A B with rightwards arrow on top equals B with rightwards arrow on top minus A with rightwards arrow on top stack A B with rightwards arrow on top equals open square brackets table row 3 row 6 end table close square brackets minus open square brackets table row cell negative 1 end cell row 3 end table close square brackets stack A B with rightwards arrow on top equals open square brackets table row cell 3 plus 1 end cell row cell 6 minus 3 end cell end table close square brackets stack A B with rightwards arrow on top equals open square brackets table row 4 row 3 end table close square brackets end style 

Maka vektor satuan begin mathsize 14px style stack A B with rightwards arrow on top end style adalah :

begin mathsize 14px style V e k t o r space s a t u a n space stack A B with rightwards arrow on top equals fraction numerator stack A B with rightwards arrow on top over denominator open vertical bar stack A B with rightwards arrow on top close vertical bar end fraction V e k t o r space s a t u a n space stack A B with rightwards arrow on top equals fraction numerator 1 over denominator square root of 4 squared plus 3 squared end root end fraction open square brackets table row 4 row 3 end table close square brackets V e k t o r space s a t u a n space stack A B with rightwards arrow on top equals fraction numerator 1 over denominator square root of 16 plus 9 end root end fraction open square brackets table row 4 row 3 end table close square brackets V e k t o r space s a t u a n space stack A B with rightwards arrow on top equals fraction numerator 1 over denominator square root of 25 end fraction open square brackets table row 4 row 3 end table close square brackets end style 

 

 

 

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