Diketahui . Jika g(x) = f(1 - x), maka kurva g naik pada...

Diketahui $begin mathsize 12px style f open parentheses x close parentheses equals 1 third x cubed plus x squared minus 3 x plus 10 end style$ . Jika g(x) = f(1 - x), maka kurva g naik pada...

$begin mathsize 12px style 0 less or equal than x less or equal than 3 end style$
$begin mathsize 12px style negative 1 less or equal than x less or equal than 3 end style$
$begin mathsize 12px style negative 3 less or equal than x less or equal than 3 end style$
$begin mathsize 12px style negative 3 less or equal than x less or equal than 1 end style$
$begin mathsize 12px style negative 4 less or equal than x less or equal than 0 end style$

Jawaban:

Diketahui $begin mathsize 12px style f open parentheses x close parentheses equals 1 third x cubed plus x squared minus 3 x plus 10 end style$ . Jika g(x) = f(1 - x), maka:

$begin mathsize 12px style g left parenthesis x right parenthesis equals 1 third open parentheses 1 minus x close parentheses cubed plus open parentheses 1 minus x close parentheses squared minus 3 open parentheses 1 minus x close parentheses plus 10 g left parenthesis x right parenthesis equals 1 third open parentheses 1 minus x close parentheses cubed plus open parentheses 1 minus x close parentheses squared plus 3 x plus 7 end style$

kurva naik, maka:

$size 12px g size 12px apostrophe open parentheses size 12px x close parentheses size 12px greater than size 12px 0 size 12px g size 12px apostrophe open parentheses size 12px x close parentheses size 12px equals size 12px minus size 12px 1 open parentheses size 12px 1 size 12px minus size 12px x close parentheses to the power of size 12px 2 size 12px minus size 12px 2 open parentheses size 12px 1 size 12px minus size 12px x close parentheses size 12px plus size 12px 3 size 12px minus open parentheses size 12px 1 size 12px minus size 12px 2 size 12px x size 12px plus size 12px x to the power of size 12px 2 close parentheses size 12px minus size 12px 2 size 12px plus size 12px 2 size 12px x size 12px plus size 12px 3 size 12px greater than size 12px 0 size 12px minus size 12px 1 size 12px plus size 12px 2 size 12px x size 12px minus size 12px x to the power of size 12px 2 size 12px plus size 12px 2 size 12px x size 12px plus size 12px 1 size 12px greater than size 12px 0 size 12px minus size 12px x to the power of size 12px 2 size 12px plus size 12px 4 size 12px x size 12px greater than size 12px 0 size 12px minus size 12px x open parentheses size 12px x size 12px minus size 12px 4 close parentheses size 12px greater than size 12px 0$

Dengan menggunakan garis bilangan

Sehingga g(x) akan naik pada selang 0 < x < 4

Jawaban yang mendekati yaitu pilihan A. $begin mathsize 12px style 0 less or equal than x less or equal than 3 end style$

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Download di Google Play

Download di Appstore

Produk Ruangguru

Produk Lainnya

Bantuan & Panduan

Hubungi Kami

081578200000

[email protected]

02140008000

Ikuti Kami

Instagram

Facebook

Twitter

Youtube