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Diketahui sin α cos β=31​ dan (α+β)=65π​. Nilai sin(α - β) = ....

Pertanyaan

Diketahui begin mathsize 14px style sin space alpha space cos space beta equals begin inline style 1 third end style end style dan begin mathsize 14px style left parenthesis alpha plus beta right parenthesis equals begin inline style fraction numerator 5 straight pi over denominator 6 end fraction end style end style. Nilai sin(α - β) = ....

  1. begin mathsize 14px inline style negative 5 over 6 end style

  2. begin mathsize 14px inline style negative 1 half end style

  3. begin mathsize 14px inline style negative 1 over 6 end style

  4. begin mathsize 14px inline style 1 over 6 end style

  5. begin mathsize 14px inline style 1 half end style

Y. Laksmi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Pembahasan

begin mathsize 14px inline style bold i bold right parenthesis bold space Jabarkan space bentuk space sin invisible function application left parenthesis straight alpha minus straight beta right parenthesis  sin invisible function application open parentheses straight alpha minus straight beta close parentheses equals sin invisible function application space straight alpha space cos space invisible function application straight beta minus cos space invisible function application straight alpha space sin invisible function application space straight beta  sin invisible function application open parentheses straight alpha minus straight beta close parentheses equals 1 third minus cos space invisible function application straight alpha space sin space invisible function application straight beta    bold ii bold right parenthesis bold space Cari space nilai space cos space invisible function application straight alpha space space sin space invisible function application straight beta space menggunakan space sin invisible function application left parenthesis straight alpha plus straight beta right parenthesis  sin invisible function application open parentheses straight alpha plus straight beta close parentheses equals sin space invisible function application straight alpha space cos space invisible function application straight beta plus cos space invisible function application straight alpha space sin invisible function application space straight beta  sin invisible function application fraction numerator 5 straight pi over denominator 6 end fraction equals 1 third plus cos space invisible function application straight alpha space sin space invisible function application straight beta  1 half equals 1 third plus cos space invisible function application straight alpha space sin space invisible function application straight beta  cos space invisible function application straight alpha space sin invisible function application space straight beta equals 1 half minus 1 third  cos space invisible function application straight alpha space sin space invisible function application straight beta equals 1 over 6    bold iii bold right parenthesis bold space Substitusi space ke space persamaan space awal  sin invisible function application open parentheses straight alpha minus straight beta close parentheses equals 1 third minus cos space invisible function application straight alpha space sin space invisible function application straight beta  sin invisible function application open parentheses straight alpha minus straight beta close parentheses equals 1 third minus 1 over 6  sin invisible function application open parentheses straight alpha minus straight beta close parentheses equals 1 over 6 end style

218

4.8 (7 rating)

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Perhatikan gambar di bawah. Tunjukkan bahwa sin15∘=46​−2​​!

59

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Jawaban terverifikasi

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