Iklan

Pertanyaan

Buatlah contoh persamaan dua lingkaran berpotongan tegak lurus!

Buatlah contoh persamaan dua lingkaran berpotongan tegak lurus!

  1. undefined 

  2. undefined 

8 dari 10 siswa nilainya naik

dengan paket belajar pilihan

Habis dalam

00

:

21

:

38

:

17

Klaim

Iklan

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

Persamaan lingkaran tersebut adalah dan dua lingkaran dikatakan berpotongan saling tegak lurus jika

Persamaan lingkaran tersebut adalah begin mathsize 14px style x squared plus y squared plus 8 x minus 10 y plus 5 equals 0 end style dan begin mathsize 14px style x squared plus y squared minus 12 x minus 10 y minus 3 equals 0 end style 
dua lingkaran dikatakan berpotongan saling tegak lurus jika begin mathsize 14px style open parentheses P subscript 1 P subscript 2 close parentheses squared equals r subscript 1 squared plus r subscript 2 squared end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell P subscript 1 open parentheses negative A over 2 comma negative B over 2 close parentheses end cell row blank blank cell P subscript 1 open parentheses negative 8 over 2 comma negative fraction numerator open parentheses negative 10 close parentheses over denominator 2 end fraction close parentheses end cell row blank blank cell P subscript 1 open parentheses negative 4 comma 5 close parentheses end cell row cell r subscript 1 end cell equals cell square root of open parentheses negative 4 close parentheses squared plus 5 squared minus 5 end root end cell row cell space space space end cell equals cell square root of 16 plus 25 minus 5 end root end cell row cell space space space end cell equals 6 end table end style       

             begin mathsize 14px style P subscript 2 left parenthesis negative A over 2 comma negative B over 2 right parenthesis P subscript 2 left parenthesis negative fraction numerator left parenthesis negative 12 right parenthesis over denominator 2 end fraction comma negative fraction numerator left parenthesis negative 10 right parenthesis over denominator 2 end fraction right parenthesis P subscript 2 left parenthesis 6 comma 5 right parenthesis r subscript 2 equals square root of 6 squared plus 5 squared plus 3 end root space space space equals square root of 36 plus 25 plus 3 end root space space space equals 8 end style                       

           

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses P subscript 1 P subscript 2 close parentheses squared end cell equals cell r subscript 1 squared plus r subscript 2 squared end cell row cell open parentheses square root of open parentheses 6 minus open parentheses negative 4 close parentheses close parentheses squared plus open parentheses 5 minus 5 close parentheses squared end root close parentheses squared end cell equals cell 6 squared plus 8 squared end cell row cell space space space space space space space space space open parentheses square root of 10 squared plus 0 end root close parentheses squared space space end cell equals cell 36 plus 64 end cell row 100 equals 100 end table end style 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Iklan

Pertanyaan serupa

Perhatikan gambar berikut. a. Tuliskah persamaan kedua lingkaran tersebut.

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia