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Pertanyaan

x → 0 lim ​ sin 2 x 3 x cos x ​ = ...

  1. 0

  2. 2 over 3

  3. 1

  4. 3 over 2

  5. infinity

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I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

Ingat kembali rumus sudut rangkap: sin 4x = 2 sin 2x cos 2x Maka, Jawaban D

Ingat kembali rumus sudut rangkap:

sin 4x = 2 sin 2x cos 2x

Maka,

limit as x rightwards arrow 0 of fraction numerator 3 x space cos space x over denominator sin space 2 x end fraction  equals limit as x rightwards arrow 0 of fraction numerator 3 x space cos space x over denominator 2 space sin space x space cos space x end fraction  equals limit as x rightwards arrow 0 of open parentheses 3 over 2 close parentheses open parentheses fraction numerator x over denominator sin space x end fraction close parentheses open parentheses fraction numerator cos space x over denominator cos space x end fraction close parentheses  equals open parentheses 3 over 2 close parentheses open parentheses 1 close parentheses open parentheses 1 close parentheses  equals 3 over 2

Jawaban D

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Nilai x → 0 lim ​ sin 4 x ⋅ tan x 3 x ⋅ tan 2 x ⋅ cos x ​ = ....

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