Nilai x→0lim 2x . sin 2x1−cos x= .....

Pertanyaan

Nilai $begin mathsize 14px style limit as x rightwards arrow 0 of invisible function application space fraction numerator 1 minus cos space invisible function application x over denominator 2 x space. space sin space invisible function application 2 x end fraction equals end style$ .....

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

$begin mathsize 14px style limit as straight x rightwards arrow 0 of invisible function application space fraction numerator 1 minus cos space invisible function application straight x over denominator 2 straight x straight space. straight space sin space invisible function application 2 straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application fraction numerator 2 space sin to the power of 2 space end exponent invisible function application 4 straight x over denominator straight space sin invisible function application space 2 straight x straight space. tan invisible function application space 2 straight x end fraction limit as straight x rightwards arrow 0 of invisible function application space fraction numerator 2. sin space invisible function application 4 straight x. sin space invisible function application 4 straight x over denominator straight space sin invisible function application space 2 straight x straight space. tan space invisible function application 2 straight x end fraction equals 8 Ingat space sifat comma bullet space limit as straight x rightwards arrow 0 of invisible function application space fraction numerator sin invisible function application space straight x over denominator straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application space fraction numerator straight x over denominator sin space invisible function application straight x end fraction equals 1 bullet space limit as straight x rightwards arrow 0 of invisible function application space fraction numerator tan invisible function application space straight x over denominator straight x end fraction equals limit as straight x rightwards arrow 0 of invisible function application space fraction numerator straight x over denominator tan invisible function application space straight x end fraction equals 1 end style$