Pertanyaan

Diketahui fungsi f ( x ) = 3 x − 1 2 x − 1 . Turunan pertama fungsi f ( x ) adalah f ( x ) . Nilai dari f ( 1 ) = ....

$Diketahui fungsi f (x) = \frac{2 x - 1}{3 x - 1} . Turunan pertama fungsi f (x) adalah f (x) . Nilai dari f (1) = ....$

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$I n g a t factorial F u n g s i space b e r b e n t u k space f left parenthesis x right parenthesis equals u over v M a k a space t u r u n a n space p e r t a m a n y a space y a i t u colon space f to the power of apostrophe left parenthesis x right parenthesis equals fraction numerator u to the power of apostrophe. v minus u. v to the power of apostrophe over denominator v squared end fraction D i k e t a h u i colon f left parenthesis x right parenthesis equals fraction numerator 2 x minus 1 over denominator 3 x minus 1 end fraction M i s a l colon u equals 2 x minus 1 left right arrow u to the power of apostrophe equals 2 v equals 3 x minus 1 left right arrow v to the power of apostrophe equals 3 M a k a colon f apostrophe left parenthesis x right parenthesis equals fraction numerator 2 left parenthesis 3 x minus 1 right parenthesis minus left parenthesis 2 x minus 1 right parenthesis left parenthesis 3 right parenthesis over denominator left parenthesis 3 x minus 1 right parenthesis squared end fraction f to the power of apostrophe left parenthesis x right parenthesis equals fraction numerator 6 x minus 2 minus 6 x plus 3 over denominator left parenthesis 3 x minus 1 right parenthesis squared end fraction f to the power of apostrophe left parenthesis x right parenthesis equals fraction numerator 1 over denominator left parenthesis 3 x minus 1 right parenthesis squared end fraction f to the power of apostrophe left parenthesis 1 right parenthesis equals fraction numerator 1 over denominator left parenthesis 3 left parenthesis 1 right parenthesis minus 1 right parenthesis squared end fraction f to the power of apostrophe left parenthesis 1 right parenthesis equals 1 fourth J a d i comma space n i l a i space d a r i space f to the power of apostrophe left parenthesis 1 right parenthesis space a d a l a h space 1 fourth.$