Pertanyaan

Invers fungsi f ( x ) = x − 1 x + 2 , x  = − 1 adalah ....

$Invers fungsi f (x) = \frac{x + 2}{x - 1}, x \neq = - 1 adalah ....$

$f apostrophe left parenthesis x right parenthesis equals fraction numerator x plus 2 over denominator x minus 1 end fraction semicolon space x not equal to 1$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator x minus 2 over denominator x minus 1 end fraction semicolon space x not equal to 1$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator x plus 2 over denominator x plus 1 end fraction semicolon space x not equal to negative 1$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator x plus 1 over denominator x plus 2 end fraction semicolon space x not equal to negative 2$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator x minus 1 over denominator x plus 2 end fraction semicolon space x not equal to negative 2$

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Y. Laksmi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Pembahasan

$Cari space invers space dengan space formula space berikut space straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator ax plus straight b over denominator cx plus straight d end fraction space rightwards double arrow space straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator negative dx plus straight b over denominator cx minus straight a end fraction straight f left parenthesis straight x right parenthesis equals fraction numerator straight x plus 2 over denominator straight x minus 1 end fraction Dengan space straight a equals 1 comma space straight b equals 2 comma space straight c equals 1 space dan space straight d equals negative 1 comma space maka straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator negative left parenthesis negative 1 right parenthesis straight x plus 2 over denominator straight x minus 1 end fraction straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator straight x plus 2 over denominator straight x minus 1 end fraction semicolon space straight x not equal to 1$