Pertanyaan

Fungsi f : R → R didefinisikan oleh f ( x ) = 2 + x 3 x + 5 , x  = − 2. Invers f ( x ) adalah f − 1 ( x ) = ....

$Fungsi f : R \to R didefinisikan oleh f (x) = \frac{3 x + 5}{2 + x}, x \neq = - 2. Invers f (x) adalah f^{- 1} (x) = ....$

$fraction numerator 2 x plus 5 over denominator x plus 3 end fraction comma space x not equal to negative 3$
$fraction numerator 2 x minus 5 over denominator x plus 3 end fraction comma space x not equal to negative 3$
$fraction numerator 2 x minus 5 over denominator 3 minus x end fraction comma space x not equal to 3$
$fraction numerator 5 x plus 2 over denominator 3 x plus 1 end fraction comma space x not equal to negative 1 third$
$fraction numerator 5 x minus 2 over denominator 3 x minus 1 end fraction comma space x not equal to 1 third$

Y. Endah

Master Teacher

Mahasiswa/Alumni Institut Teknologi Bandung

Jawaban terverifikasi

Pembahasan

$Ingat space cara space cepat space invers space colon straight f left parenthesis straight x right parenthesis space equals space fraction numerator ax plus straight b over denominator cx plus straight d end fraction space maka space inversnya space straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis space equals space fraction numerator dx minus straight b over denominator negative cx plus straight a end fraction straight f left parenthesis straight x right parenthesis space equals space fraction numerator 3 straight x plus 5 over denominator straight x plus 2 end fraction straight f to the power of apostrophe left parenthesis straight x right parenthesis space equals space fraction numerator 2 straight x minus 5 over denominator negative straight x plus 3 end fraction comma space x not equal to 3$