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Persamaan lingkaran dengan pusat (5,2) dan berdiameter 213​ adalah....

Pertanyaan

P e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space left parenthesis 5 comma 2 right parenthesis space d a n space b e r d i a m e t e r space 2 square root of 13 space a d a l a h....

  1. x squared plus y squared plus 10 x plus 4 y plus 34 equals 0

  2. x squared plus y squared plus 4 x plus 10 y plus 16 equals 0

  3. x squared plus y squared minus 4 x minus 10 y plus 16 equals 0

  4. x squared plus y squared minus 10 x minus 4 y plus 16 equals 0

  5. x squared plus y squared minus 10 x minus 4 y plus 34 equals 0

F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

d equals 2 square root of 13 rightwards double arrow r equals square root of 13 space  P e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space left parenthesis h comma space k right parenthesis space d a n space j a r i space – space j a r i space r space a d a l a h  left parenthesis x minus h right parenthesis squared plus left parenthesis y minus k right parenthesis squared equals r squared    M a k a space p e r s a m a a n space l i n g k a r a n space d e n g a n space p u s a t space left parenthesis 5 comma 2 right parenthesis space d a n space r equals square root of 13  left parenthesis x minus 5 right parenthesis squared plus left parenthesis y minus 2 right parenthesis squared equals open parentheses square root of 13 close parentheses squared  x squared minus 10 x plus 25 plus y squared minus 4 y plus 4 equals 13  x squared plus y squared minus 10 x minus 4 y plus 25 plus 4 minus 13 equals 0  x squared plus y squared minus 10 x minus 4 y plus 16 equals 0

98

4.3 (3 rating)

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Tentukan persamaan lingkaran jika diketahui: b. pusat pada garis x−y−1=0, melalui titik (0,0), dan berjari-jari 5​.

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5.0

Jawaban terverifikasi

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