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Pertanyaan

A g a r p ers amaan k u a d r a t 4 x 2 − ( p − 3 ) x + 1 = 0 m e m p u n y ai d u a aka r t i d ak n y a t a , maka ni l ai p y an g m e m e n u hi a d a l ah ....

  1. undefined

  2. negative 7 less than p less than 1

  3. 1 less than p less than 7

  4. p less than negative 1 space a t a u space p greater than 7

  5. p less than 1 space a t a u space p greater than 7

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F. Pratama

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Pembahasan

S y a r a t space d a r i space p e r s a m a a n space k u a d r a t space a x squared plus b x plus c equals 0 space m e m i i k i space a k a r – a k a r space t i d a k space n y a t a space m a k a space n i l a i space  h a r u s space D less than 0  b squared minus 4 a c less than 0 left parenthesis negative left parenthesis p minus 3 right parenthesis right parenthesis squared minus 4 left parenthesis 4 right parenthesis left parenthesis 1 right parenthesis less than 0  p squared minus 6 p plus 9 minus 16 less than 0  p squared minus 6 p minus 7 less than 0  left parenthesis p minus 7 right parenthesis left parenthesis p plus 1 right parenthesis less than 0    J a d i space H p equals negative 1 less than p less than 7

 

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Tentukanlah nilai x yang membuat grafik fungsi y = 4 x 2 + 3 x − 2 berada di bawah grafik fungsi y = 3 x 2 + 4 x + 18 .

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