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Pertanyaan

open parentheses cosx plus sinx close parentheses squared over open parentheses cosx minus sinx close parentheses squared equals...

  1. fraction numerator 1 over denominator 1 minus cos 2 straight x end fraction

  2. fraction numerator 1 over denominator 1 minus sin 2 straight x end fraction

  3. fraction numerator 1 plus cos 2 straight x over denominator 1 minus cos 2 straight x end fraction

  4. fraction numerator 1 plus 2 sinx over denominator 1 minus 2 sinx end fraction

  5. 1 plus sin 2 straight x

H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

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Pembahasan

open parentheses cos space x space plus space sin space x close parentheses squared over open parentheses cos space x space minus space sin space x close parentheses squared equals fraction numerator begin display style cos squared end style begin display style x end style begin display style plus end style begin display style begin display style sin end style squared end style begin display style plus end style begin display style 2 end style begin display style sin end style begin display style x end style begin display style. end style begin display style cos end style begin display style x end style over denominator cos squared x plus sin squared minus 2 sin x. cos x end fraction  equals fraction numerator 1 plus 2 sin x. cos x over denominator 1 minus 2 sin x. cos x end fraction  equals fraction numerator begin display style 1 plus sin 2 x end style over denominator begin display style 1 minus sin 2 x end style end fraction

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Jika tan2θ−sin2θ=x dan tan2θ+sin2θ=y, tunjukkan bahwa: b. (x2−y2)2=16xy

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