Roboguru

5. Jika   (1)   (2)   (3)    (4)   Pernyataan yang benar adalah...

Pertanyaan

5. Jika begin mathsize 14px style a with rightwards arrow on top equals 2 i with hat on top minus j with hat on top plus 3 k with hat on top space dan space b with rightwards arrow on top equals negative 4 i with hat on top plus 2 j with hat on top minus 6 k with hat on top comma end style 

(1) begin mathsize 14px style open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals square root of 14 end style 

(2) begin mathsize 14px style open vertical bar a with rightwards arrow on top close vertical bar colon open vertical bar b with rightwards arrow on top close vertical bar equals 1 colon 2 end style 

(3) begin mathsize 14px style a with rightwards arrow on top bullet b with rightwards arrow on top equals negative 28 end style  

(4) begin mathsize 14px style a with rightwards arrow on top divided by divided by b with rightwards arrow on top end style 

Pernyataan yang benar adalah...undefined 

  1. (1), (2), dan (3)  space 

  2. (1) dan (3)undefined 

  3. (2) dan (4) 

  4. (4)undefined 

  5. (1), (2), (3), dan (4)undefined 

Pembahasan Soal:

Perhatikan penghitungan berikut!

begin mathsize 14px style a with rightwards arrow on top equals open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses space semicolon space b with rightwards arrow on top equals open parentheses table row cell negative 4 end cell row 2 row cell negative 6 end cell end table close parentheses  left parenthesis 1 right parenthesis space open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar a with rightwards arrow on top plus b with rightwards arrow on top equals open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses plus open parentheses table row cell negative 4 end cell row 2 row cell negative 6 end cell end table close parentheses equals open parentheses table row cell negative 2 end cell row 1 row cell negative 3 end cell end table close parentheses open vertical bar a with rightwards arrow on top plus b with rightwards arrow on top close vertical bar equals square root of open parentheses negative 2 close parentheses squared plus 1 squared plus open parentheses negative 3 close parentheses squared end root equals square root of 14   left parenthesis 2 right parenthesis space open vertical bar a with rightwards arrow on top close vertical bar colon open vertical bar b with rightwards arrow on top close vertical bar open vertical bar a with rightwards arrow on top close vertical bar equals square root of 2 squared plus open parentheses negative 1 close parentheses squared plus 3 squared end root equals square root of 14 open vertical bar b with rightwards arrow on top close vertical bar equals square root of open parentheses negative 4 close parentheses squared plus 2 squared plus open parentheses negative 6 close parentheses squared end root equals square root of 56 open vertical bar a with rightwards arrow on top close vertical bar colon open vertical bar b with rightwards arrow on top close vertical bar equals square root of 14 colon square root of 56 equals 1 colon 4  left parenthesis 3 right parenthesis space a with rightwards arrow on top bullet b with rightwards arrow on top open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses bullet open parentheses table row cell negative 4 end cell row 2 row cell negative 6 end cell end table close parentheses equals 2 open parentheses negative 4 close parentheses plus 2 open parentheses negative 1 close parentheses plus 3 open parentheses negative 6 close parentheses equals negative 28  left parenthesis 4 right parenthesis space a with rightwards arrow on top divided by divided by b with rightwards arrow on top a with rightwards arrow on top equals open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses space minus 2 a with rightwards arrow on top equals negative 2 open parentheses table row 2 row cell negative 1 end cell row 3 end table close parentheses space equals open parentheses table row cell negative 4 end cell row 2 row cell negative 6 end cell end table close parentheses equals b with rightwards arrow on top vektor space a with rightwards arrow on top space jika space diperbesar space 2 space satuan space maka space akan space menjadi space vektor space b with rightwards arrow on top comma sehingga space vektor space a with rightwards arrow on top divided by divided by b with rightwards arrow on top  end style 

Pernyataan yang benar adalah (1),(3), dan (4). Jika disesuaikan dengan pilihan jawaban yang tersedia maka penyataan yang sesuai yaitu (1) dan (3).

Oleh karena itu, jawaban yang benar adalah B. undefined 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 13 Maret 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved