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Pertanyaan

Titik (4,-:B) dicerminkan terhadap garis x = 6, dilanjutkan dengan rotasi (0,60°), hasilnya adalah ...... .

Titik (4,-:B) dicerminkan terhadap garis x = 6, dilanjutkan dengan rotasi (0,60°), hasilnya
adalah ...... .

  1. left parenthesis negative 4 space plus space 4 square root of 3 comma 4 space minus 4 square root of 3 right parenthesis

  2. left parenthesis negative 4 space plus space 4 square root of 3 comma negative 4 space minus 4 square root of 3 right parenthesis

  3. left parenthesis 4 space plus space 4 square root of 3 comma negative 4 space minus 4 square root of 3 right parenthesis

  4. left parenthesis 4 space plus space 4 square root of 3 comma 4 space minus 4 square root of 3 right parenthesis

  5. left parenthesis 4 space plus space 4 square root of 3 comma 4 square root of 3 minus 4 right parenthesis

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T i t i k space P space left parenthesis x comma y right parenthesis space d i c e r m i n space t e r h a d a p space x space equals space a space b a y a n g a n space a d a l a h space P apostrophe space left parenthesis 2 a minus x comma y right parenthesis.  T i t i apostrophe k space P space left parenthesis space 4 comma negative 8 right parenthesis space d j c e r r m i n space t e r h a d a p space x space equals space 6 space b a y a n g a n space a d a l a h space p apostrophe space left parenthesis 2.6 minus 4 space comma negative 8 space right parenthesis space equals space left parenthesis 8 comma negative 8 right parenthesis.  S e l a n j u t n y a space t i t i k space P apostrophe space left parenthesis 2 comma negative 8 right parenthesis space d i r o t a s i k a n space left parenthesis 0 comma 600 right parenthesis space u n t u k space m e n g h a s i l k a n space b a y a n g a n space h a s i l space P left parenthesis x " comma y " right parenthesis  p apostrophe left parenthesis 8 comma space 8 right parenthesis stack rightwards arrow P left parenthesis x " comma y " right parenthesis with r o t left parenthesis 0 comma 60 right parenthesis on top  open parentheses table row cell cos space 60 end cell cell negative sin space 60 end cell row cell sin space 60 end cell cell cos space 60 end cell end table close parentheses equals open parentheses table row cell 1 half end cell cell negative 1 half square root of 3 end cell row cell 1 half square root of 3 end cell cell 1 half end cell end table close parentheses  open parentheses table row cell x " end cell row cell y " end cell end table close parentheses equals space open parentheses table row cell 1 half end cell cell negative 1 half square root of 3 end cell row cell 1 half square root of 3 end cell cell 1 half end cell end table close parentheses space open parentheses table row 8 row cell negative 8 end cell end table close parentheses  open parentheses table row cell x " end cell row cell y " end cell end table close parentheses equals open parentheses table row cell 4 plus 4 square root of 3 end cell row cell 4 square root of 3 minus 4 end cell end table close parentheses  J a d i comma space b a y a n g a n space a d a l a h space a k h i r n y a space a d a l a h space left parenthesis 4 plus 4 square root of 3 comma 4 square root of 3 minus 4 right parenthesis

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Kurva y = x 2 + 2 x + 3 dirotasikan sebesar 9 0 ∘ dengan pusat titik O(0, 0), lalu dicerminkan terhadap garis x = 3. Persamaan bayangan kurva tersebut adalah.. . .

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