Iklan

Pertanyaan

Persamaan peta garis 2x - y + 5 = 0 karena refleksi terhad'ap garis x + 3 =.0 dilanjutkan degan transformasi yang bersesuaian dengan ( − 2 − 1 ​ 4 1 ​ ) matriks adalah ...

Persamaan peta garis 2x - y + 5 = 0 karena refleksi terhad'ap garis x + 3 =.0 dilanjutkan degan
transformasi yang bersesuaian dengan  matriks adalah ...

  1. 3x - 10y + 17 = 0

  2. 3x-10y + 14 = 0

  3. 3x - 10y - 14 = 0

  4. 3x + 2y - 7 = 0

  5. X + 2y - 14 = .0

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

00

:

01

:

22

:

04

Klaim

Iklan

R. RGFLSATU

Master Teacher

Jawaban terverifikasi

Pembahasan

G a r i s space x space plus space 3 space equals space 0 space tilde space x space equals space minus 3  p left parenthesis x comma Y right parenthesis rightwards arrow with r e f l e k s i space x equals negative 3 on top equals p apostrophe left parenthesis 2 a minus x comma y right parenthesis  2 X minus y plus 5 equals 0 rightwards arrow with r e f l e k s i space x equals negative 3 on top 2 open parentheses 2 open parentheses negative 3 close parentheses minus x close parentheses minus y plus 5 equals 0  rightwards arrow 2 left parenthesis negative 6 space minus space x right parenthesis space minus space y space plus 5 space equals space 0  rightwards arrow negative 2 x minus space y minus 7 space equals space 0  G a r i s space minus 2 x space minus space y space minus 7 space equals space 0 space i n i space d i t r a n s f o r m a s i k a n space o l e h space m a t r i k s space open parentheses table row cell negative 2 end cell 4 row cell negative 1 end cell 1 end table close parentheses space B a y a n g a n n y a space d t e n t u k a n space s e b g a i space b e r i k u t  open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals open parentheses table row cell negative 2 end cell 4 row cell negative 1 end cell 1 end table close parentheses open parentheses table row x row y end table close parentheses  open parentheses table row x row y end table close parentheses equals open parentheses table row cell negative 2 end cell 4 row cell negative 1 end cell 1 end table close parentheses to the power of negative 1 end exponent open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses  open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals fraction numerator 1 over denominator negative 2 plus 4 end fraction open parentheses table row cell negative 2 end cell 4 row cell negative 1 end cell 1 end table close parentheses open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses  open parentheses table row cell 1 half end cell cell negative 2 end cell row cell 1 half end cell 1 end table close parentheses open parentheses table row cell x apostrophe end cell row cell y apostrophe end cell end table close parentheses equals open parentheses table row cell 1 half x apostrophe end cell cell negative 2 x apostrophe end cell row cell 1 half y apostrophe end cell cell negative y apostrophe end cell end table close parentheses    D i p e r o l e h colon space times  x equals 1 half x apostrophe minus 2 y apostrophe  y apostrophe equals 1 half x apostrophe minus y apostrophe  S u b s i t u s i k a n space h a r g a minus h a r g a space i n i space k e space d a l a m space p e r s a m a a n space g a r i s minus 2 x minus y minus 7 equals 0  left right double arrow negative 2 open parentheses 1 half x apostrophe minus 2 y apostrophe close parentheses minus open parentheses 1 half x apostrophe minus y apostrophe close parentheses minus 7 equals 0  left right double arrow negative x apostrophe plus space 4 y apostrophe minus 1 half x apostrophe plus space y apostrophe minus space 7 space equals space 0  left right double arrow negative 3 over 2 x space apostrophe space plus 5 y apostrophe space minus 7 space equals space 0  left right double arrow 3 x apostrophe minus 10 y apostrophe plus space 14 space equals space 0  left right double arrow 3 x space minus 10 y space plus space 14 space equals space 0

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

48

Iklan

Pertanyaan serupa

Diketahui bayangan kurva y = x 2 oleh pencerminan terhadap garis y = − x dilanjutkan oleh matriks ( 1 − 1 ​ 0 1 ​ ) dan akan memotong sumbu y di titik ....

4

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia