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Tentukan nilai x→2lim​ x2−5x+63x2−8x+4​=....

Pertanyaan

Tentukan nilai begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals.... end style 

W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

 begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals negative 4 end style.

Pembahasan

begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals limit as x rightwards arrow 2 of space fraction numerator open parentheses 3 x minus 2 close parentheses open parentheses x minus 2 close parentheses over denominator open parentheses x minus 3 close parentheses open parentheses x minus 2 close parentheses end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals limit as x rightwards arrow 2 of space fraction numerator 3 x minus 2 over denominator x minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 3 open parentheses 2 close parentheses minus 2 over denominator 2 minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 6 minus 2 over denominator 2 minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 4 over denominator negative 1 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals negative 4 end style  

Jadi, begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals negative 4 end style.

27

5.0 (1 rating)

Pertanyaan serupa

Nilai dari x→1lim​4x2−4x5x3−5x2−3x+3​ adalah . . . .

19

5.0

Jawaban terverifikasi

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