Pertanyaan

Tentukan nilai x → 2 lim x 2 − 5 x + 6 3 x 2 − 8 x + 4 = ....

Tentukan nilai $x \to 2 lim \frac{3 x ^{2} - 8 x + 4}{x ^{2} - 5 x + 6} = ....$

W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

.

$begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals negative 4 end style$ .

Pembahasan

Jadi, .

$begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals limit as x rightwards arrow 2 of space fraction numerator open parentheses 3 x minus 2 close parentheses open parentheses x minus 2 close parentheses over denominator open parentheses x minus 3 close parentheses open parentheses x minus 2 close parentheses end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals limit as x rightwards arrow 2 of space fraction numerator 3 x minus 2 over denominator x minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 3 open parentheses 2 close parentheses minus 2 over denominator 2 minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 6 minus 2 over denominator 2 minus 3 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 4 over denominator negative 1 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals negative 4 end style$

Jadi, $begin mathsize 14px style limit as x rightwards arrow 2 of space fraction numerator 3 x squared minus 8 x plus 4 over denominator x squared minus 5 x plus 6 end fraction equals negative 4 end style$ .