Hasil dari f (−1)=x→−1lim​x+1x3​+3​ adalah ...

Pertanyaan

Hasil dari begin mathsize 14px style f apostrophe left parenthesis negative 1 right parenthesis equals limit as x rightwards arrow negative 1 of fraction numerator begin display style 3 over x end style plus 3 over denominator x plus 1 end fraction end style adalah ...

  1. ...

  2. ...undefined

M. Nasrullah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Makassar

Jawaban terverifikasi

Jawaban

begin mathsize 14px style f apostrophe left parenthesis negative 1 right parenthesis equals negative 3 end style

Pembahasan

Untuk menyelesaikan soal limit di atas kita tidak dapat menggunakan cara subtitusi karena akan menghasilkan penyebut 0. Maka kita dapat menggunakan cara pemfaktoran:

table attributes columnalign right center left columnspacing 0px end attributes row cell size 14px f size 14px apostrophe size 14px left parenthesis size 14px minus size 14px 1 size 14px right parenthesis end cell size 14px equals cell size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 1 below fraction numerator begin mathsize 14px display style 3 over x plus 3 end style over denominator size 14px x size 14px plus size 14px 1 end fraction end cell row blank size 14px equals cell size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 1 below fraction numerator begin mathsize 14px display style 3 open parentheses 1 over x plus 1 close parentheses end style over denominator size 14px x size 14px plus size 14px 1 end fraction end cell row blank size 14px equals cell size 14px 3 size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 1 below fraction numerator begin display style size 14px 1 over size 14px x end style size 14px plus begin display style size 14px x over size 14px x end style over denominator size 14px x size 14px plus size 14px 1 end fraction end cell row blank size 14px equals cell size 14px 3 size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 1 below fraction numerator begin mathsize 14px display style fraction numerator x plus 1 over denominator x end fraction end style over denominator size 14px x size 14px plus size 14px 1 end fraction end cell row blank size 14px equals cell size 14px 3 size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 1 below fraction numerator begin mathsize 14px style left parenthesis x plus 1 right parenthesis end style over denominator size 14px x begin mathsize 14px style left parenthesis x plus 1 right parenthesis end style end fraction end cell row blank size 14px equals cell size 14px 3 size 14px lim with size 14px x size 14px rightwards arrow size 14px minus size 14px 1 below size 14px 1 over size 14px x end cell row blank size 14px equals cell size 14px 3 fraction numerator size 14px 1 over denominator begin mathsize 14px style left parenthesis negative 1 right parenthesis end style end fraction end cell row blank size 14px equals cell fraction numerator size 14px 3 over denominator size 14px minus size 14px 1 end fraction end cell row blank size 14px equals cell size 14px minus size 14px 3 end cell row blank blank blank end table 

Jadi, begin mathsize 14px style f apostrophe left parenthesis negative 1 right parenthesis equals negative 3 end style

8

0.0 (0 rating)

Pertanyaan serupa

x→−2lim​ (x2−5x−3)=....

11

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Produk Lainnya

Fitur Roboguru

Topik Roboguru

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia