Pertanyaan

Tentukan kebenaran hubungan berikut! a = 3 ∑ 8 a = a = 2 ∑ 7 ( a + 1 )

Tentukan kebenaran hubungan berikut!

$a = 3 \sum 8 a = a = 2 \sum 7 (a + 1)$

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Habis dalam

Klaim

G. Albiah

Master Teacher

Mahasiswa/Alumni Universitas Galuh Ciamis

Jawaban terverifikasi

Jawaban

hubungan terbukti.

hubungan

table attributes columnalign right center left columnspacing 0px end attributes row cell sum from straight a equals 3 to 8 of straight a end cell equals cell sum from straight a equals 2 to 7 of open parentheses straight a plus 1 close parentheses end cell end table

terbukti.

Pembahasan

Mencai nilai Mencari nilai Maka, Jadi, hubungan terbukti.

Mencai nilai sum from a equals 3 to 8 of a

$table attributes columnalign right center left columnspacing 0px end attributes row cell sum from a equals 3 to 8 of a end cell equals cell sum from a equals 1 to 8 of a minus sum from a equals 1 to 2 of a end cell row blank equals cell 1 half times thin space 8 open parentheses 8 plus 1 close parentheses minus 1 half times thin space 2 open parentheses 2 plus 1 close parentheses end cell row blank equals cell 8 times thin space 9 times 1 half minus fraction numerator 1 times thin space 2 open parentheses 2 plus 1 close parentheses over denominator 2 end fraction end cell row blank equals cell fraction numerator 1 times thin space 8 times thin space 9 over denominator 2 end fraction minus 1 times thin space 3 end cell row blank equals cell 72 over 2 minus 3 end cell row blank equals cell 36 minus 3 end cell row blank equals 33 end table$

Mencari nilai sum from a equals 2 to 7 of open parentheses a plus 1 close parentheses

$table attributes columnalign right center left columnspacing 0px end attributes row cell sum from a equals 2 to 7 of open parentheses a plus 1 close parentheses end cell equals cell sum from a equals 1 to 7 of a plus 1 minus sum from a equals 1 to 1 of a plus 1 end cell row blank equals cell open square brackets 1 half times thin space 7 open parentheses 7 plus 1 close parentheses plus 7 close square brackets minus open square brackets 1 half times thin space 1 times open parentheses 1 plus 1 close parentheses plus 1 close square brackets end cell row blank equals cell open square brackets 7 times thin space 8 times 1 half plus 1 times thin space 7 plus 7 close square brackets minus open square brackets 1 times thin space 2 times 1 half plus 1 close square brackets end cell row blank equals cell open square brackets fraction numerator 1 times thin space 7 times thin space 8 over denominator 2 end fraction plus 7 close square brackets minus open square brackets 1 times fraction numerator 1 times thin space 2 over denominator 2 end fraction plus 1 close square brackets end cell row blank equals cell open square brackets 56 over 2 plus 7 close square brackets minus open square brackets 1 times thin space 1 plus 1 close square brackets end cell row blank equals cell open square brackets 28 plus 7 close square brackets minus open square brackets 1 plus 1 close square brackets end cell row blank equals cell 35 minus 2 end cell row blank equals 33 end table$

Maka,

table attributes columnalign right center left columnspacing 0px end attributes row cell sum from straight a equals 3 to 8 of straight a end cell equals cell sum from straight a equals 2 to 7 of open parentheses straight a plus 1 close parentheses end cell row 33 equals cell 33 space left parenthesis terbukti right parenthesis end cell end table

Jadi, hubungan table attributes columnalign right center left columnspacing 0px end attributes row cell sum from straight a equals 3 to 8 of straight a end cell equals cell sum from straight a equals 2 to 7 of open parentheses straight a plus 1 close parentheses end cell end table terbukti.