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Tentukan bentuk sederhana dari cos 20∘sec 40∘ tan 130∘sin 70∘sec 140∘ tan50∘​

Pertanyaan

Tentukan bentuk sederhana dari fraction numerator sin space 70 degree s e c space 140 degree space tan 50 degree over denominator cos space 20 degree s e c space 40 degree space tan space 130 degree end fraction

 

I. Roy

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

table attributes columnalign right center left columnspacing 0px end attributes row cell sin space 70 degree end cell equals cell sin open parentheses 90 minus 20 close parentheses degree end cell row blank equals cell cos space 20 end cell row cell sec space 140 degree end cell equals cell sec open parentheses 180 minus 40 close parentheses end cell row blank equals cell negative sec space 40 degree end cell row cell tan space 130 degree end cell equals cell tan open parentheses 180 minus 50 close parentheses end cell row blank equals cell negative tan space 50 degree end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator sin space 70 degree s e c space 140 degree space tan 50 degree over denominator cos space 20 degree s e c space 40 degree space tan space 130 degree end fraction end cell equals cell fraction numerator cos space 20 degree times negative s e c space 40 degree times tan space 50 degree over denominator cos space 20 degree times s e c space 40 degree times negative tan space 50 degree end fraction end cell row blank equals cell fraction numerator negative 1 over denominator negative 1 end fraction end cell row blank equals 1 end table

Jadi, bentuk sederhana dari fraction numerator sin space 70 degree s e c space 140 degree space tan 50 degree over denominator cos space 20 degree s e c space 40 degree space tan space 130 degree end fraction adalah 1

 

79

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