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Suatu larutan mengandung ion , , , dan  masing-mas...

Suatu larutan mengandung ion begin mathsize 14px style Ag to the power of plus sign end stylebegin mathsize 14px style Ca to the power of 2 plus end exponent end stylebegin mathsize 14px style Mg to the power of 2 plus sign end style, dan begin mathsize 14px style Al to the power of 3 plus sign end style masing-masing dengan konsentrasi 0,10 M. Jika ditambahkan larutan begin mathsize 14px style Na subscript 3 P O subscript 4 end style, endapan yang terbentuk paling bawah adaalah...

  1. begin mathsize 14px style Ag subscript 3 P O subscript 4 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 16 end exponent end style)

  2. begin mathsize 14px style Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 33 end exponent end style)

  3. begin mathsize 14px style Mg subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 24 end exponent end style)

  4. begin mathsize 14px style Al P O subscript 4 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 20 end exponent end style)

  5. begin mathsize 14px style Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style dan begin mathsize 14px style Ag subscript 3 P O subscript 4 end style

Jawaban:

a. begin mathsize 14px style Ag subscript 3 P O subscript 4 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 16 end exponent end style)


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Ksp equals cell left parenthesis 0 comma 1 right parenthesis cubed cross times s 1 comma 0 cross times 10 to the power of negative sign 16 end exponent equals 10 to the power of negative sign 3 end exponent cross times s end cell row s equals cell 1 comma 0 cross times 10 to the power of negative sign 13 end exponent space M end cell end table end style


b. begin mathsize 14px style Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 33 end exponent end style)



begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Ksp equals cell left parenthesis 0 comma 1 right parenthesis cubed cross times left parenthesis 2 s right parenthesis squared end cell row cell 1 comma 0 cross times 10 to the power of negative sign 33 end exponent end cell equals cell 10 to the power of negative sign 3 end exponent cross times 4 s squared end cell row cell s squared end cell equals cell 0 comma 25 cross times 10 to the power of negative sign 30 end exponent end cell row s equals cell 5 cross times 10 to the power of negative sign 16 end exponent space M end cell end table end style


c. begin mathsize 14px style Mg subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 24 end exponent end style)



begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Ksp equals cell left parenthesis 0 comma 1 right parenthesis cubed cross times left parenthesis 2 s right parenthesis squared end cell row cell 1 comma 0 cross times 10 to the power of negative sign 24 end exponent end cell equals cell 10 to the power of negative sign 3 end exponent cross times 4 s squared end cell row cell s squared end cell equals cell 10 to the power of negative sign 21 end exponent end cell row s equals cell 10 to the power of negative sign 11 comma 5 end exponent space M end cell end table end style


d. begin mathsize 14px style Al P O subscript 4 end style (Ksp= begin mathsize 14px style 1 comma 0 cross times 10 to the power of negative sign 20 end exponent end style)



begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row Ksp equals cell left parenthesis 0 comma 1 right parenthesis to the power of 1 cross times s end cell row cell 1 comma 0 cross times 10 to the power of negative sign 20 end exponent end cell equals cell 10 to the power of negative sign 1 end exponent cross times s end cell row s equals cell 1 comma 0 cross times 10 to the power of negative sign 19 end exponent space M end cell end table end style

 

Larutan yang terletak paling bawah adalah larutan yang memiliki nilai kelarutan terkecil.

Jadi, jawabannya adalah D.

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