Pertanyaan

Simpangan baku dari data 2,1,1,10,8,2,3,5 adalah ....

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

Pertama, kita cari terlebih dahulu nilai rata-ratanya. Sehingga kita peroleh simpangan bakunya

Pertama, kita cari terlebih dahulu nilai rata-ratanya.

$begin mathsize 12px style x with minus on top equals fraction numerator 2 plus 1 plus 1 plus 10 plus 8 plus 2 plus 3 plus 5 over denominator 8 end fraction equals 32 over 8 equals 4 end style$

Sehingga kita peroleh simpangan bakunya

$begin mathsize 12px style sigma squared equals fraction numerator sum from i equals 1 to n of open parentheses x subscript i minus x with minus on top close parentheses squared over denominator n end fraction sigma squared equals fraction numerator open parentheses 2 minus 4 close parentheses squared plus open parentheses 1 minus 4 close parentheses squared plus open parentheses 1 minus 4 close parentheses squared plus open parentheses 10 minus 4 close parentheses squared over denominator 8 end fraction sigma squared equals fraction numerator open parentheses 8 minus 4 close parentheses squared plus open parentheses 2 minus 4 close parentheses squared plus open parentheses 3 minus 4 close parentheses squared plus open parentheses 5 minus 4 close parentheses squared over denominator 8 end fraction sigma squared equals fraction numerator 4 plus 9 plus 9 plus 36 plus 16 plus 4 plus 1 plus 1 over denominator 8 end fraction sigma squared equals 80 over 8 sigma squared equals 10 sigma equals square root of 10 end style$