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Selesaikan soal berikut dengan substitusi!

Pertanyaan

Selesaikan soal berikut dengan substitusi!

begin mathsize 14px style integral x to the power of 4 open parentheses x to the power of 5 plus 3 close parentheses to the power of 6 d x end style

Pembahasan Soal:

Misalkan: , maka bentuk aljabar pada integral dapat dituliskan sebagai berikut

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell integral left parenthesis x to the power of 5 plus 3 right parenthesis to the power of 6 times x to the power of 4 d x end cell equals cell integral u to the power of 6 fraction numerator d u over denominator 5 end fraction end cell row blank equals cell 1 fifth integral u to the power of 6 d u end cell row blank equals cell 1 fifth left parenthesis 1 over 7 u to the power of 7 plus C right parenthesis end cell row blank equals cell u to the power of 7 over 35 plus C end cell row blank blank blank end table end style

Substitusikan pemisalan u, pada hasil integral

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell u to the power of 7 over 35 plus C end cell equals cell open parentheses x to the power of 5 plus 3 close parentheses to the power of 7 over 35 plus C end cell row blank equals cell 1 over 35 open parentheses x to the power of 5 plus 3 close parentheses to the power of 7 plus C end cell end table end style

Jadi, begin mathsize 14px style integral x to the power of 4 open parentheses x to the power of 5 plus 3 close parentheses to the power of 6 d x end styleError converting from MathML to accessible text..

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 April 2021

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