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Sebanyak 100 mL larutan CH 3 ​ COONa mempunyai pH = 10. Jika K a ​ CH 3 ​ COOH = 1 0 − 5 dan Mr = 82, tentukan massa garam CH 3 ​ COONa yang terlarut dalam 100 mL larutan !

Sebanyak 100 mL larutan  mempunyai pH = 10. Jika  dan Mr undefined = 82, tentukan massa garam  yang terlarut dalam 100 mL larutan undefined!

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M. Dwiyanti

Master Teacher

Mahasiswa/Alumni Universitas Negeri Yogyakarta

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Jawaban

massa garam yang terlarut adalah 82 gram.

massa garam begin mathsize 14px style C H subscript 3 C O O Na end style yang terlarut adalah 82 gram.

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Pembahasan

Langkah 1: menghitung Langkah 2: menghitung Langkah 3: menghitung massa Jadi, massa garam yang terlarut adalah 82 gram.

Langkah 1: menghitung begin mathsize 14px style begin bold style open square brackets O H to the power of minus sign close square brackets end style end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell pKw bond pH end cell row blank equals cell 14 minus sign 10 end cell row blank equals 4 end table end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pOH equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row 4 equals cell negative sign log space open square brackets O H to the power of minus sign close square brackets end cell row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 4 end exponent end cell end table end style 


Langkah 2: menghitung begin mathsize 14px style begin bold style open square brackets C H subscript 3 C O O Na close square brackets end style end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell square root of K subscript w over K subscript a open square brackets C H subscript 3 C O O Na close square brackets end root end cell row cell 10 to the power of negative sign 4 end exponent end cell equals cell square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent open square brackets C H subscript 3 C O O Na close square brackets end root end cell row cell open parentheses 10 to the power of negative sign 4 end exponent close parentheses squared end cell equals cell open parentheses square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent open square brackets C H subscript 3 C O O Na close square brackets end root close parentheses squared end cell row cell 10 to the power of negative sign 8 end exponent end cell equals cell 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent open square brackets C H subscript 3 C O O Na close square brackets end cell row cell open square brackets C H subscript 3 C O O Na close square brackets end cell equals cell fraction numerator 10 to the power of negative sign 8 end exponent cross times 10 to the power of negative sign 5 end exponent over denominator 10 to the power of negative sign 14 end exponent end fraction end cell row blank equals cell 10 space M end cell end table end style


Langkah 3: menghitung massa begin mathsize 14px style C H subscript bold 3 C O O Na end style

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets C H subscript 3 C O O Na close square brackets end cell equals cell m over Mr cross times 1000 over V end cell row cell 10 space M end cell equals cell m over 82 cross times fraction numerator 1000 over denominator 100 space mL end fraction end cell row m equals cell 82 space gram end cell row blank blank blank end table end style

Jadi, massa garam begin mathsize 14px style C H subscript 3 C O O Na end style yang terlarut adalah 82 gram.

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