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Proyeksi skalar vektor a pada b adalah 6. Vektor a = ⎝ ⎛ ​ x − 4 y ​ ⎠ ⎞ ​ dan b = ⎝ ⎛ ​ − 2 1 2 ​ ⎠ ⎞ ​ dengan ∣ ∣ ​ a ∣ ∣ ​ = 89 ​ , maka nilai

Proyeksi skalar vektor  pada  adalah 6. Vektor  dan  dengan , maka nilai x equals... 

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nilai yang memenuhi adalah atau

nilai x yang memenuhi adalah negative 8 atau negative 3 

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Diketahui proyeksi skalar vektor pada adalah 6. Vektor dan , maka: , maka: Substitusi (1) ke (2), maka: Jadi, nilai yang memenuhi adalah atau

Diketahui proyeksi skalar vektor a with rightwards arrow on top pada b with rightwards arrow on top adalah 6. Vektor a with rightwards arrow on top equals open parentheses table row x row cell negative 4 end cell row y end table close parentheses dan b with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row 1 row 2 end table close parentheses, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar c with rightwards arrow on top close vertical bar end cell equals cell fraction numerator a with rightwards arrow on top. b with rightwards arrow on top over denominator open vertical bar b with rightwards arrow on top close vertical bar end fraction end cell row 6 equals cell fraction numerator left parenthesis x right parenthesis left parenthesis negative 2 right parenthesis plus left parenthesis negative 4 right parenthesis left parenthesis 1 right parenthesis plus left parenthesis y right parenthesis left parenthesis 2 right parenthesis over denominator square root of left parenthesis negative 2 right parenthesis squared plus 1 squared plus 2 squared end root end fraction end cell row 6 equals cell fraction numerator negative 2 x minus 4 plus 2 y over denominator square root of 4 plus 1 plus 4 end root end fraction end cell row 6 equals cell fraction numerator negative 2 x plus 2 y minus 4 over denominator 3 end fraction end cell row 18 equals cell negative 2 x plus 2 y minus 4 end cell row cell 2 x minus 2 y end cell equals cell negative 4 minus 18 end cell row cell 2 x minus 2 y end cell equals cell negative 22 end cell row cell x minus y end cell equals cell negative 11 end cell row y equals cell x plus 11 space............. space left parenthesis 1 right parenthesis end cell end table 

open vertical bar a with rightwards arrow on top close vertical bar equals square root of 89, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar a with rightwards arrow on top close vertical bar end cell equals cell square root of x squared plus left parenthesis negative 4 right parenthesis squared plus y squared end root end cell row cell square root of 89 end cell equals cell square root of x squared plus 16 plus y squared end root end cell row 89 equals cell x squared plus y squared plus 16 end cell row cell x squared plus y squared end cell equals cell 73 space........... space left parenthesis 2 right parenthesis end cell end table

Substitusi (1) ke (2), maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell x squared plus left parenthesis x plus 11 right parenthesis squared end cell equals cell 73 space end cell row cell x squared plus x squared plus 22 x plus 121 minus 73 end cell equals 0 row cell 2 x squared plus 22 x plus 48 end cell equals 0 row cell x squared plus 11 x plus 24 end cell equals 0 row cell left parenthesis x plus 8 right parenthesis left parenthesis x plus 3 right parenthesis end cell equals 0 end table

 x equals negative 8 space atau space x equals negative 3 

Jadi, nilai x yang memenuhi adalah negative 8 atau negative 3 

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