Roboguru

Pertanyaan

Persamaan bayangan lingkaran begin mathsize 14px style x squared plus y squared equals 4 end style bila dicerminkan terhadap garis x = 2 dan dilanjutkan dengan translasi begin mathsize 14px style open parentheses table row cell negative 3 end cell row 4 end table close parentheses end style adalah ....

  1. begin mathsize 14px style x squared plus y squared minus 2 x minus 8 y plus 13 equals 0 end style

  2. begin mathsize 14px style x squared plus y squared plus 2 x minus 8 y plus 13 equals 0 end style

  3. begin mathsize 14px style x squared plus y squared minus 2 x plus 8 y plus 13 equals 0 end style

  4. begin mathsize 14px style x squared plus y squared plus 2 x plus 8 y plus 13 equals 0 end style

  5. begin mathsize 14px style x squared plus y squared plus 8 x minus 2 y plus 13 equals 0 end style

S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Pembahasan

begin mathsize 14px style open parentheses table row straight x row straight y end table close parentheses rightwards arrow with straight M subscript straight x equals 2 end subscript on top straight space open parentheses table row cell straight x straight apostrophe end cell row cell straight y straight apostrophe end cell end table close parentheses equals open parentheses table row cell 2 open parentheses 2 close parentheses minus straight x end cell row straight y end table close parentheses rightwards arrow with straight T equals open parentheses table row cell negative 3 end cell row 4 end table close parentheses on top open parentheses table row cell straight x double apostrophe end cell row cell straight y double apostrophe end cell end table close parentheses equals open parentheses table row cell 4 minus straight x end cell row straight y end table close parentheses plus open parentheses table row cell negative 3 end cell row 4 end table close parentheses equals open parentheses table row cell 1 minus straight x end cell row cell straight y plus 4 end cell end table close parentheses    Jadi comma space straight x apostrophe apostrophe equals 1 minus straight x rightwards double arrow straight x equals 1 minus straight x apostrophe apostrophe  straight y to the power of double apostrophe equals straight y plus 4 rightwards double arrow straight y equals straight y to the power of double apostrophe minus 4    Sehingga space  straight x squared plus straight y squared equals 4 rightwards double arrow left parenthesis 1 minus straight x apostrophe apostrophe right parenthesis squared plus left parenthesis straight y apostrophe apostrophe minus 4 right parenthesis squared equals 4  open parentheses straight x to the power of double apostrophe close parentheses squared plus open parentheses straight y to the power of double apostrophe close parentheses squared minus 2 straight x to the power of double apostrophe minus 8 straight y to the power of double apostrophe plus 13 equals 0 end style

34

0.0 (0 rating)

Pertanyaan serupa

Jika elips x2+3y2=1 dicerminkan terhadap sumbu x kemudian digeser 1 ke kiri akan mempunyai persamaan ...

83

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ruangguru WhatsApp

081578200000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2022 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia