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Persamaan bayangan lingkaran x 2 + y 2 = 4 bila dicerminkan terhadap garis x = 2 dan dilanjutkan dengan translasi ( − 3 4 ​ ) adalah ....

Persamaan bayangan lingkaran bila dicerminkan terhadap garis x = 2 dan dilanjutkan dengan translasi  adalah ....

  1. begin mathsize 14px style x squared plus y squared minus 2 x minus 8 y plus 13 equals 0 end style

  2. begin mathsize 14px style x squared plus y squared plus 2 x minus 8 y plus 13 equals 0 end style

  3. begin mathsize 14px style x squared plus y squared minus 2 x plus 8 y plus 13 equals 0 end style

  4. begin mathsize 14px style x squared plus y squared plus 2 x plus 8 y plus 13 equals 0 end style

  5. begin mathsize 14px style x squared plus y squared plus 8 x minus 2 y plus 13 equals 0 end style

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S. Intan

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

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begin mathsize 14px style open parentheses table row straight x row straight y end table close parentheses rightwards arrow with straight M subscript straight x equals 2 end subscript on top straight space open parentheses table row cell straight x straight apostrophe end cell row cell straight y straight apostrophe end cell end table close parentheses equals open parentheses table row cell 2 open parentheses 2 close parentheses minus straight x end cell row straight y end table close parentheses rightwards arrow with straight T equals open parentheses table row cell negative 3 end cell row 4 end table close parentheses on top open parentheses table row cell straight x double apostrophe end cell row cell straight y double apostrophe end cell end table close parentheses equals open parentheses table row cell 4 minus straight x end cell row straight y end table close parentheses plus open parentheses table row cell negative 3 end cell row 4 end table close parentheses equals open parentheses table row cell 1 minus straight x end cell row cell straight y plus 4 end cell end table close parentheses    Jadi comma space straight x apostrophe apostrophe equals 1 minus straight x rightwards double arrow straight x equals 1 minus straight x apostrophe apostrophe  straight y to the power of double apostrophe equals straight y plus 4 rightwards double arrow straight y equals straight y to the power of double apostrophe minus 4    Sehingga space  straight x squared plus straight y squared equals 4 rightwards double arrow left parenthesis 1 minus straight x apostrophe apostrophe right parenthesis squared plus left parenthesis straight y apostrophe apostrophe minus 4 right parenthesis squared equals 4  open parentheses straight x to the power of double apostrophe close parentheses squared plus open parentheses straight y to the power of double apostrophe close parentheses squared minus 2 straight x to the power of double apostrophe minus 8 straight y to the power of double apostrophe plus 13 equals 0 end style

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Diberikan kurva E ≡ y = 2 x + x . Kurva E dicerminkan terhadap garis x + 3 = 0 , kemudian dilanjutkan oleh translasi T = ( − 2 3 ​ ) . Tuliskan persamaan bayangan kurva tersebut.

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