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Pertanyaan

Penyelesaian pertidaksamaan 8 1 2 x − 1 ​ 1 ​ ≤ 2 7 2 − x adalah ....

Penyelesaian pertidaksamaan  adalah ....

  1. x greater or equal than 4 

  2. x less or equal than negative 4 

  3. x greater or equal than negative 4 

  4. x less or equal than 4 over 7 

  5. x greater or equal than negative 4 over 7 

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W. Lestari

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

Pembahasan

Ingat kembali bentuk persamaan eksponen berikut: Diketahuipertidaksamaan , maka: Jadi, jawaban yang benar adalah C.

Ingat kembali bentuk persamaan eksponen berikut:

a to the power of f open parentheses x close parentheses end exponent less or equal than a to the power of g open parentheses x close parentheses end exponent space rightwards arrow space f open parentheses x close parentheses less or equal than g open parentheses x close parentheses space open square brackets untuk space a greater than 1 close square brackets 

Diketahui pertidaksamaan fraction numerator 1 over denominator square root of 81 to the power of 2 x minus 1 end exponent end root end fraction less or equal than 27 to the power of 2 minus x end exponent, maka:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 1 over denominator square root of 81 to the power of 2 x minus 1 end exponent end root end fraction end cell less or equal than cell 27 to the power of 2 minus x end exponent end cell row cell fraction numerator 1 over denominator square root of open parentheses 3 to the power of 4 close parentheses to the power of 2 x minus 1 end exponent end root end fraction end cell less or equal than cell open parentheses 3 cubed close parentheses to the power of 2 minus x end exponent end cell row cell fraction numerator 1 over denominator square root of 3 to the power of 4 open parentheses 2 x minus 1 close parentheses end exponent end root end fraction end cell less or equal than cell 3 to the power of 6 minus 3 x end exponent end cell row cell 1 over open parentheses 3 to the power of 4 open parentheses 2 x minus 1 close parentheses end exponent close parentheses to the power of begin display style 1 half end style end exponent end cell less or equal than cell 3 to the power of 6 minus 3 x end exponent end cell row cell 1 over 3 to the power of begin display style fraction numerator 4 open parentheses 2 x minus 1 close parentheses over denominator 2 end fraction end style end exponent end cell less or equal than cell 3 to the power of 6 minus 3 x end exponent end cell row cell 1 over 3 to the power of 2 open parentheses 2 x minus 1 close parentheses end exponent end cell less or equal than cell 3 to the power of 6 minus 3 x end exponent end cell row cell 3 to the power of negative 2 open parentheses 2 x minus 1 close parentheses end exponent end cell less or equal than cell 3 to the power of 6 minus 3 x end exponent end cell row cell 3 to the power of negative 4 x plus 2 end exponent end cell less or equal than cell 3 to the power of 6 minus 3 x end exponent end cell row cell negative 4 x plus 2 end cell less or equal than cell 6 minus 3 x end cell row cell negative 4 x plus 3 x end cell less or equal than cell 6 minus 2 end cell row cell negative x end cell less or equal than 4 row x greater or equal than cell negative 4 end cell end table 

Jadi, jawaban yang benar adalah C.

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